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kotegsom [21]
2 years ago
10

0 ÷ 0 = 1

Mathematics
1 answer:
TEA [102]2 years ago
7 0

Answer:

0/0 = undefined not 1

Step-by-step explanation: Undefined means there are no solutions possible for the operations in view. The example in question is itself wrong. n/0 is infinite but not undefined. 0/0 is undefined

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Nancy is replacing the mat on her trampoline. The circular mat has a diameter of 18 feet. what is the area of the trampoline mat
hjlf
Answer : 254 ft sq

A = pi x r^2

A = 3.14 x 81
7 0
3 years ago
Carlos can ride his bike 30 km in 2 hours. At the same rate, how far can he ride in 7 hours?
lozanna [386]
He can ride his bike 105 km. 30/2 is 15. 15*7 is 105.

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5 0
4 years ago
Read 2 more answers
The area of a triangle is found using the following formula:
Serjik [45]

Answer:

12

Step-by-step explanation:

a=bh x 1/2

If you plug in 3=b and 8=h it is now

a= 3 x 8 x 1/2

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Hope this helps :)

5 0
3 years ago
Will give 50 points
mafiozo [28]

Answer:

120.96$

Step-by-step explanation:

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Hope this helps!!

7 0
3 years ago
[4]
Tanya [424]

Answer:

Angle ACD = 38°

Step-by-step explanation:

The full, correct question is presented the attached image to this solution.

Given

Point O is the centre if the circle

Points A, B, C and D are points on the circle

Angle AOB = 140°

Angle OAC = 14°

Angle AOB = 2 × (Angle ACB) [angle subtended at the centre of the circle is twice the angle subtended at the circumference of the circle)

140° = 2 × (Angle ACB)

Angle ACB = (140°/2) = 70°

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180° [sun of angles in a triangle is 180°]

But Angle OAB = Angle ABO = a [base angles of an iscosceles triangle are equal since OA and OB are both radii for the circle O)

(Angle AOB) + (Angle OAB) + (Angle ABO) = 180°

140° + a + a = 180°

2a = 40°

a = (40/2) = 20°

Angle OAB = Angle ABO = 20°

Angle CAB = (Angle OAC) + (Angle OAB) = 14° + 20° = 34°

Triangle ADC is an iscosceles triangle, hence,

Angle DAC = Angle ACD = x [base angles of an iscosceles triangle are equal]

But

(Angle DCB) + (Angle DAB) = 180° [Opposite angles of a cyclic quadilateral (a quadilateral inscribed in a circle) sum up to give 180°]

Angle DCB = (Angle DCA) + (Angle ACB) = (x + 70°)

Angle DAB = (Angle DAC) + (Angle CAB) = (x + 34°)

(Angle DCB) + (Angle DAB) = 180°

(x + 70°) + (x + 34°) = 180°

2x + 104° = 180°

2x = 180° - 104° = 76°

x = (76°/2) = 38°

Angle DAC = Angle ACD = 38°

Angle ACD = 38°

Hope this Helps!!!

7 0
3 years ago
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