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never [62]
2 years ago
7

In addition to the facts in the diagram which statements is necessary to prove that the two triangles are congruent by the SAS c

riterion
Mathematics
2 answers:
atroni [7]2 years ago
6 0
The angles should be included between the equal sides
insens350 [35]2 years ago
4 0

the answer is c bc=ef

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I need help for these 2 problems the reason it’s already written is because I got them wrong (20 pts)
lawyer [7]

Answer:

I'm so so sorry but I cant really see what those say... Again, I'm very sorry about this...

Step-by-step explanation:

8 0
2 years ago
Which statement is true about the extreme value of the given quadratic equation?
ICE Princess25 [194]

Answer:

Option B.  The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

The correct quadratic equation is

y=-3x^{2}+12x-33

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

Convert to vertex form

Factor -3

y=-3(x^{2}-4x)-33

Complete the square

y=-3(x^{2}-4x+2^2)-33+12

y=-3(x^{2}-4x+4)-21

Rewrite as perfect squares

y=-3(x-2)^{2}-21

The vertex is the point (2,-21)

therefore

The equation has a maximum value with a y-coordinate of -21

3 0
3 years ago
X+y= -9<br> x+2y= -25<br><br> According to the system of equations above, what is the value of y?
Varvara68 [4.7K]
Try this option:
if x+y=-9 is I (one)
and x+2y=-25 is II (two), then
if II-I, then (x+2y)-(x+y)=-25+9 ⇔ y=-16.
6 0
3 years ago
The length of a rectangle is 5 ft less than three times the width, and the area of the rectangle is 50 ft². Find the dimensions
Mariulka [41]

Answer

Length = 10 ft

Width = 5 ft

Explanation

Area of the rectangle given = 50 ft²

Let the width of the rectangle be x

So this means the length of the rectangle will be 3x - 5

What to find:

The dimensions of the rectangle.

Step-by-step solution:

Area of a rectangle = length x width

i.e A = L x W

Put A = 50, L = 3x - 5, W = x into the formula.

\begin{gathered} 50=(3x-5)x \\ 50=3x^2-5x \\ 3x^2-5x-50=0 \end{gathered}

The quadratic equation can now be solve using factorization method:

\begin{gathered} 3x^2-5x-50=0 \\ 3x^2-15x+10x-50=0 \\ 3x(x-5)+10(x-5)=0 \\ (3x+10)(x-5)=0 \\ 3x+10=0\text{ }or\text{ }x-5=0 \\ 3x=-10\text{ }or\text{ }x=5 \\ x=-\frac{10}{3}\text{ }or\text{ }x=5 \end{gathered}

Since the dimension can not be negative, hence the value of x will be = 5.

Therefore, the dimensions of the rectangle will be:

\begin{gathered} Length=3x-5=3(5)-5=15-5=10\text{ }ft \\  \\ Width=x=5\text{ }ft \end{gathered}

7 0
11 months ago
5.<br> Solve<br> 3/5x + 1/3 &lt;4/5x+-1/3
mihalych1998 [28]

Answer:

Inequality form: x>10/3

Interval Notation: (10/3, infinity)

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

3 0
2 years ago
Read 2 more answers
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