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Vsevolod [243]
2 years ago
15

Several students tested plant growth for given conditions. Which student’s data is most representative of average plant growth f

or the tested conditions?
Mathematics
2 answers:
gulaghasi [49]2 years ago
4 0
More info plz?
Not clear question
Citrus2011 [14]2 years ago
4 0

Alicia tested 6 plants.

Brenden tested 24 plants.

Caitlin tested 3 plants.

Diego tested 12 plants.

This is the info and

Alicia

Brenden

Caitlin

Diego

are the anser choices

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A right rectangular pyramid is sliced parallel to the base, as shown.
ELEN [110]

The answer would be the first choice.  15 cm^{2}

Explanation: The reason for this is that the question was pretty much just asking what the area of the resulting two-dimensional cross section would be -the shape in gray- (which can be found by using the formula lw. To add on, since the dimensions of the shape are already given (5 and 3) all you've to do is multiply: 3*5=15

That's how you get to the answer.

7 0
3 years ago
Read 2 more answers
​ Quadrilateral ABCD ​ is inscribed in this circle.
Anna [14]
A quadrilateral, has 4 sides and its internal angles sum, add up to 360, now... you have 3 angles give.. .but we don't have C

so.. C is the difference of all the three angles from 360 or  \bf \measuredangle C=360-x-(2x+1)-148\implies \measuredangle C=360-x-2x-1-148   whatever that is, now, you'll get some value in x-terms

so.... now once we know what C is

you can if you want, do a search in google for "inscribed quadrilateral conjecture",  I can do a quick proof if you need one

but in short, for a quadrilateral inscribed in a circle, each pair of opposites angles are "supplementary angles", namely they add up to 180°

so.. what the dickens does all that mean?   well D+B=180 and A+C = 180

now. we know what A is, 2x+1
and by now, you'd know what C is from  360-x-2x-1-148

so... add them together then   and

\bf \begin{array}{cccclllll}
A&+&C&=&180\\
\uparrow &&\uparrow \\
(2x+1)&+&(360-x-2x-1-148)&=&180
\end{array}

solve for "x"


6 0
3 years ago
Read 2 more answers
The blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 247.9 and a standard deviation of
labwork [276]

Answer:

A) Approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 118.5 and 377.3 = 95%

B) approximate percentage of women with platelet counts between 53.8 and 442.0 = 99.7%

Step-by-step explanation:

We are given;

mean;μ = 247.9

standard deviation;σ = 64.7

A) We want to find the approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 118.5 and 377.3.

Now, from the image attached, we can see that from the empirical curve, the probability of 1 standard deviation from the mean is (34% + 34%) = 68 %.

While probability of 2 standard deviations from the mean is (13.5% + 34% + 34% + 13.5%) = 95%

Thus, approximate percentage of women with platelet counts within 2 standard deviations of the​ mean, or between 118.5 and 377.3 = 95%

B) Now, we want to find the approximate percentage of women with platelet counts between 53.8 and 442.0.

53.8 and 442.0 represents 3 standard deviations from the mean.

Let's confirm that.

Since mean;μ = 247.9

standard deviation;σ = 64.7 ;

μ = 247.9

σ = 64.7

μ + 3σ = 247.9 + 3(64.7) = 442

Also;

μ - 3σ = 247.9 - 3(64.7) = 53.8

Again from the empirical curve attached, we cans that at 3 standard deviations from the mean, we have a percentage probability of;

(2.35% + 13.5% + 34% + 34% + 13.5% + 2.35%) = 99.7%

5 0
3 years ago
Given that tan(θ) ≈ -4.580 where 3π/2<θ<2π, find the values of sin(θ) and cos(θ)
OleMash [197]

Answer:

You put the lime in the coconut

Step-by-step explanation:

My wife is dead.

5 0
2 years ago
Please do all of them correct and quick I will mark brainliest and 10 points ty pls I’m on a time limit
sweet-ann [11.9K]

1: 9pi

2. 18

3. 12pi

4. 672

5. 23.94

6. 10 3/4

7 0
3 years ago
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