Answer:
23,325 ft, about 4.42 miles
Step-by-step explanation:
The geometry of the situation can be modeled by a right triangle, where the side adjacent to the 2.7° angle of climb is the horizontal distance, and the side opposite is the vertical change in altitude. That change is ...
5600 ft -4500 ft = 1100 ft
and the angle relation is ...
tan(2.7°) = opposite/adjacent = (1100 ft)/(horizontal distance)
Multiplying this equation by (horizontal distance)/tan(2.7°) gives ...
horizontal distance = (1100 ft)/tan(2.7°) ≈ 23,325 ft
Dividing this by 5280 ft/mi gives ...
horizontal distance ≈ 4.42 mi
The airplane travels about 23,325 ft, or 4.42 miles, horizontally as it climbs.
