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Ede4ka [16]
4 years ago
7

23, 69, 207, 621 What is the 7th term of this sequence?

Mathematics
1 answer:
Phoenix [80]4 years ago
7 0
You are multiplying 3 each time.

23 x 3 = 69

69 x 3 = 207

207 x 3 = 621 

621 is the 4th term

621 x 3 = 1863

1863 x 3 = 5589

5589 x 3 = 16767


16767 is your 7th term in this sequence

hope this helps
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Points def are parallel
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4 years ago
Help plz i will give brainist
Lemur [1.5K]

Answer:

Hes correct with number 1 aka answer A

Step-by-step explanation:

Its talking abt in the middle hes suppose to divide the six bc at the end it will have 1/8-1/8-1/8 and 2 negatives make a positive meaning it would be 2/8-1/8=1/8 there for number 1 aka A is right btw i want brainiest for explanation thx :)

4 0
3 years ago
Brewed decaffeinated coffee contains some caffeine. We want to estimate the amount of caffeine in 8 ounce cups of decaf coffee a
rusak2 [61]

Answer:

We would have to take a sample of 62 to achieve this result.

Step-by-step explanation:

Confidence level of 95%.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.95}{2} = 0.025

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.025 = 0.975, so Z = 1.96.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

Assume that the standard deviation in the amount of caffeine in 8 ounces of decaf coffee is known to be 2 mg.

This means that \sigma = 2

If we wanted to estimate the true mean amount of caffeine in 8 ounce cups of decaf coffee to within /- 0.5 mg, how large a sample would we have to take to achieve this result?

We would need a sample of n.

n is found when M = 0.5. So

M = z\frac{\sigma}{\sqrt{n}}

0.5 = 1.96\frac{2}{\sqrt{n}}

0.5\sqrt{n} = 2*1.96

Dividing both sides by 0.5

\sqrt{n} = 4*1.96

(\sqrt{n})^2 = (4*1.96)^2

n = 61.5

Rounding up

We would have to take a sample of 62 to achieve this result.

8 0
3 years ago
Cara has $25 to buy dry pet food a pound of dog food costs $2 and treats are $1 apiece if she buys 9 pounds of food the greatest
zzz [600]

Cost of each pound of dog food = $2 .

Total cost of 9 pounds of dog food = 9 * 2 = $18.

Let us assume number of treats she can buy = t.

Cost of each treat = $1.

Cost of t number of treats = 1*t = 1t .

Total money Cara has = $25.

We can setup an inequality as,

Total cost of dog food + total cost of t number of treats ≤ 25.

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Subtracting 18 from both sides, we get

18 + 1t -18  ≤ 25-18.

1t ≤ 7 or t ≤ 7.

So, she can purchase 7 or less treats.

5 0
3 years ago
Given the Homogeneous equation x^2ydy+xy^2dx=0, use y=ux, u=y/x and dy=udx+xdu to solve the differential equation. Solve for y.
scZoUnD [109]

Answer:

y=\frac{C}{x}.

Step-by-step explanation:

Given homogeneous equation

x^2ydy+xy^2dx=0

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Substitute y=ux , u=\frac{y}{x}

\frac{\mathrm{d}y}{\mathrm{d}x}=-\frac{y}{x}

Now,

u+x\frac{\mathrm{d}u}{\mathrm{d}x}=\frac{\mathrm{d}y}{\mathrm{d}x}

u+x\frac{\mathrm{d}u}{\mathrm{d}x}=-u

\frac{\mathrm{d}u}{\mathrm{d}x}=-2u

\frac{du}{u}=-\frac{dx}{x}

Integrating both side we get

lnu=-2lnx+lnC

Where lnC= integration constant

lnu+ln{x}^2=lnC

lnux^2=lnC

Cancel ln on both side

ux^2=C

Substitute u=\frac{y}{x}

Then we get

xy=C

y=\frac{C}{x}.

Answer:y=\frac{C}{x}.

8 0
3 years ago
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