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3 years ago

If CP =Rs. 9,000 and SP= Rs. 8,584 then Profit / loss amount is

Mathematics

1 answer:

Gemiola [76]3 years ago

8 0

Answer: Loss = Rs. 416

Step-by-step explanation:

Since CP is more than SP, it is a loss.

Loss = CP - SP

Loss = 9000 - 8584

Loss = 416

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Find the volume of each rectangular prism or cylinder with the given dimensions. Round to the nearest hundredth, if necessary.

Doss [256]

The answer is A. 60.16 ft3

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4 years ago

Please help me understand

ioda

9514 1404 393

Answer:

C. 18 inches

Step-by-step explanation:

The median of a trapezoid is the line segment that joins the midpoints of the sides of the trapezoid. It is halfway between the parallel bases, and is parallel to them. It length is the average of the lengths of the two bases:

(15 +21)/2 = 36/2 = 18 . . . . inches

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3 years ago

A car is at a distance s, in miles from its starting point in t hours, given by s(t)=10t^2. Find s(2) and s(5). Find s(5)-s(2).

weeeeeb [17]

Answer:

Average Velocity= 70 miles per hour

Step-by-step explanation:

Distance= s

Time = t

s(t)=10t^2

Putting the values

s(2) = 10 (2)^2= 10&4

s= 40

s(5) = 10 (5)^2 = 10*25

S(5)= 250

The average velocity is defined as the rate of change of speed in unit time.

Speed= distance/time

Velocity = Speed in a definite direction

Average Velocity= Displacement/ Time

Average Velocity= Change in distance/ Change in time

s(5) - s(2)/ t(5)- t(2)

= 250-40/5-2= 210/3= 70 miles per hour

4 0

3 years ago

A piece of wire 25 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

fomenos

Answer:

Wire used for square is 7.55 m.

Step-by-step explanation:

Let the length of wire cut for square be 'x'.

Given:

Total length of the wire = 25 m

Length of wire for square = 'x'

Length of wire for equilateral triangle = $25-x$

Now, area of square (a) = $x^2$

Area of equilateral triangle (e) is given as:

$e=\frac{\sqrt3}{4}(25-x)^2$

Now, total area (A) is given as:

$A=a+e\\\\A=x^2+\frac{\sqrt3}{4}(25-x)^2$

Now, in order to maximize 'A', the derivative of area with respect to 'x' must be 0.

∴ $\frac{dA}{dx}=0$

$\frac{d}{dx}(x^2+\frac{\sqrt3}{4}(25-x)^2)=0\\\\2x-\frac{\sqrt3}{2}(25-x)=0\\\\2x+\frac{x\sqrt3}{2}=\frac{25\sqrt3}{2}\\\\x(2+\frac{\sqrt3}{2})=\frac{25\sqrt3}{2}\\\\x(4+\sqrt3)=25\sqrt3\\\\x=\frac{25\sqrt3}{4+\sqrt3}=7.55\ m$

Therefore, the length of the wire that is cut for square should be 7.55 m for maximum area.

3 0

3 years ago