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2 years ago

The scatterplot that represents the monthly values of stock QRS has an r

Mathematics

1 answer:

cricket20 [7]2 years ago

4 0

Answer:

Step-by-step explanation:

The correlation coefficient, r value, measures the strength and direction of 2 variables in a scatterplot. It ranges from +1 to -1.

+1 means a perfect positive correlation

-1 means a perfect negative correlation

0 means there is no correlation

Also,

a value close to 0.7 would signify a strong relationship (whether positive or negative)

a value close to 0.5 indicates a moderate relationship

a value close to 0.3 indicates a weak relationship

Now, the question says the r value is 0.315

THis is POSITIVE

Also, this is a "weak" relationship

Thus, we can say:

It has weak correlation, or answer choice D

D is right.

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is it possible to have three points that would not fit on the same plane 2 dimensional surface? Why or why not

Alisiya [41]

<span>No. Three points could be the three points of a triangle. Triangles are two dimensional surfaces. Therefore, any three points could exist on a two dimensional triangle.</span>

3 0

3 years ago

Solve GHI. Round the answer to the nearest hundredth.

Sedaia [141]

Answer:

Part 1) $HI=15\ units$

Part 2)

Part 3) $< I=28.07\°$

The answer is the option A

Step-by-step explanation:

Part 1) Find the measure of side HI

Applying the Pythagoras Theorem

$GI^{2} =GH^{2}+HI^{2}$

substitute the values and solve for HI

$17^{2} =8^{2}+HI^{2}$

$HI^{2}=17^{2}-8^{2}$

$HI^{2}=225$

$HI=15\ units$

Part 2) Find the measure of angle G

In the right triangle GHI

$cos(G)=\frac{GH}{GI}$

substitute the values

$cos(G)=\frac{8}{17}$

$G=arccos(\frac{8}{17})=61.93\°$

Part 3) Find the measure of angle I

Remember that

The sum of the interior angles of a triangle must be equal to 180 degrees

substitute the values

$61.93\°+90\°+< I=180\°$

$< I=180\°-(61.93\°+90\°)=28.07\°$

7 0

3 years ago

Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.

k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = $\frac{3}{4}$ ,

$q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28$

= $6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28$

= $(\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28$

= $(\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}$

= $-\frac{1666}{64}$

= $-\frac{833}{32}$ ≠ 0

Therefore, Yuri is not correct. x = $\frac{3}{4}$ can not be a root of the given expression.

6 0

3 years ago

Read 2 more answers

For which independent value do the equations generate the same dependent value? y1=6x-16 , y2=3x-10

Nikitich [7]

The question asks which x-value gives the same y-value for both equations, so if you need the ys to be equal, you can set both equations equal to each other, giving you 6x-16=3x-10. Now, solve for x. 6x-16=3x-10, subtract 3x and add 16, 3x=6, divide 3, x=2. Your answer is x=2.

7 0

3 years ago

Can you please help???

marusya05 [52]

Answer:

2 or 3 I think

I gessssssssssing

5 0

2 years ago