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mr_godi [17]
3 years ago
13

There is a famous irrational number called Euler's number, symbolized with an e. Like π , its decimal fo rm never ends or repeat

s. The first few digits of e are 2.7182818284. A. Between which two square roots of integers could you find this number? _. B. Between which two square roots of integers can you find
Mathematics
2 answers:
Burka [1]3 years ago
4 0

Answer:

Step-by-step explanation:

Given that in Mathematics there is a famous irrational number called Euler's number, symbolized with an e.

This number lies between 2 and 3 and have approximate value as

2.7182818281

Since this lies between 2 and 3, the required integers would be between 4 and 9

Let us find square root of all integers from 4 to 9

\sqrt{4} =2\\\sqrt{5} =2.236\\\sqrt{6} =2.449\\\sqrt{8} =2.828

Thus this irrational numbers lies between square root of 7 and square root of 8.

defon3 years ago
3 0

\sqrt{7} < e < \sqrt{8}=2\sqrt{2}

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Which expression is equivalent to [(3xy^-5)^3/(x^-2y^2)^-4]^-2?
Mademuasel [1]

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