Question

What is the equation of the line that is parallel to the line 5x + 2y = 12 and passes through the point (−2, 4)? y = – Five-halvesx – 1 y = – Five-halvesx + 5 y = Two-fifthsx – 1 y = Two-fifthsx + 5

Answer 1

Answer:

$y= \frac{-5}{2}x-1$

Step-by-step explanation:

the line equation is  5x + 2y = 12

Solve for y to find out slope m

y=mx+b

$5x + 2y = 12$

Subtract 5x from both sides

$2y =-5x+12$

Divide both sides by 2

$y=\frac{-5}{2} x+6$

slope = -5/2

Slope of parallel lines are same . So slope of parallel line is $\frac{-5}{2}$

m=-5/2 , point (-2,4)

$y-y_1= m(x-x_1)$

$y-4= \frac{-5}{2}(x+2)$

$y-4= \frac{-5}{2}x-5$

Add 4 on both sides

$y= \frac{-5}{2}x-1$

Answer 2

Answer:

y < -5/2x – 7

Step-by-step explanation:

Just took the test, hope this helps :)