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solmaris [256]
3 years ago
7

Given a polynomial f(x), if (x + 3) is a factor, what else must be true?

Mathematics
2 answers:
Maurinko [17]3 years ago
4 0
One of the zeroes must be x=-3.
lianna [129]3 years ago
3 0

What applies here is one of the laws of the factorization of polynomials, called the factor theorem and it states that:

For a polynomial f(x) , if for any value a,  f(a) =0  then (x-a) is factor of f(x)

Example:

Consider the polynomial

f(x) = x^{3} - 3x^{2} - 8x+4

For  a =3,

f(a) = (3)^{3} - 3(3)^{2} - 8(3)+24

= 27-27-24+24 = 0

f (3)= 0

which means (x-3) is a factor of f(x)

Applying the above rule to the question:

if (x + 3) is a factor of a polynomial f(x), then f(-3) = 0

note that (x+3) can also be written  as (x- (-3)).

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Explain how you know which method you should use to solve a rational equation.
notsponge [240]

<u>Methods to solve rational equation:</u>

Rational equation:

A rational equation is an equation containing at least one rational expression.

Method 1:

The method for solving rational equations is to rewrite the rational expressions in terms of a common denominator. Then, since we know the numerators are equal, we can solve for the variable.

For example,

\frac{1}{2}=\frac{x}{2}\Rightarrow x=1

This can be used for rational equations with polynomials too.

For example,

\frac{1+x}{x-3}=\frac{4}{x-3}\Rightarrow(1+x)=4 \Rightarrow x=3

When the terms in a rational equation have unlike denominators, solving the equation will be as follows

\frac{x+2}{8}=\frac{3}{4}

\Rightarrow\frac{x+2}{1}=\frac{3\times8}{4}\Rightarrow{x+2}=2\times3

\Rightarrow{x+2}=6\Rightarrow x=6-2\Rightarrow x=4

Method 2:

Another way of solving the above equation is by finding least common denominator (LCD)

\frac{x+2}{8}=\frac{3}{4}

Factors of 4: 1\times2\times2

Factors of 8: 1\times2\times2\times2

The LCD of 4 and 8 is 8. So, we have to make the right hand side denominator as 8. This is done by the following step,

\Rightarrow\frac{x+2}{8}=\frac{3}{4}\times{2}{2}

we get,

\Rightarrow\frac{x+2}{8}=\frac{6}{8}

On cancelling 8 on both sides we get,

\Rightarrow(x+2)=6\rightarrow x=6-2\rightarrow x=4

Hence, these are the ways to solve a rational equation.

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2 years ago
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