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Nady [450]
3 years ago
13

Select the equation in which the graph of the line has a negative slope and the y-intercept equals 10.

Mathematics
1 answer:
PolarNik [594]3 years ago
3 0
That would be C.

20x + 5y = 50
5y = - 20x + 50
y = -20/5x + 50/5
y = - 4x + 10
now in y = mx + b form. the m represents ur slope and the b represents ur y intercept. So here, u have a slope of -4 and a y intercept of 10.
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Answer:

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Step-by-step explanation:

Required

Determine the relationship between given lines

(a)

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An equation written in form: y=mx + b has the slope:

m \to slope

So, in both equations:

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m_2 = \frac{2}{5}

For both lines to be parallel

m_1 = m_2

This is false in this case, because:

-\frac{2}{5} \ne \frac{2}{5}

For both lines to be perpendicular

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This is false in this case, because:

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(b)

5y + 2x = -10

and

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Write equations in form: y=mx + b

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Divide by 5

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Divide by 2

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m_1 = -\frac{2}{5}

m_2 = \frac{5}{2}

For both lines to be parallel

m_1 = m_2

This is false in this case, because:

-\frac{2}{5} \ne \frac{5}{2}

For both lines to be perpendicular

m_1 * m_2 = -1

This is true in this case, because:

-\frac{2}{5} * \frac{5}{2} = -1

Cancel out 2 and 5

-1 = -1

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Step-by-step explanation:

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