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Amanda [17]
3 years ago
5

HELP WILL MARK BRAINLIEST

Mathematics
1 answer:
Anna71 [15]3 years ago
4 0

Answer:

(-3,-1)

Step-by-step explanation:

You can graph both of the points on desmos, and then look at the slope from p1 to the midpoint. so you can get the slope, and use it to get the p2. the slope is -4/6. So you get that answer.

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Axis of sym: x =
marta [7]

Answer:

<h2>SEE BELOW</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic function
  • PEMDAS
<h3>let's solve:</h3>

vertex:(h,k)

therefore

vertex:(-1,4)

axis of symmetry:x=h

therefore

axis of symmetry:x=-1

  • to find the quadratic equation we need to figure out the vertex form of quadratic equation and then simply it to standard form i.e ax²+bx+c=0

vertex form of quadratic equation:

  • y=a(x-h)²+k

therefore

  • y=a(x-(-1))²+4
  • y=a(x+1)²+4

it's to notice that we don't know what a is

therefore we have to figure it out

the graph crosses y-asix at (0,3) coordinates

so,

3=a(0+1)²+4

simplify parentheses:

3 = a(1 {)}^{2}  + 4

simplify exponent:

3 =  a + 4

therefore

a =  - 1

our vertex form of quadratic equation is

  • y=-(x+1)²+4

let's simplify it to standard form

simplify square:

y =  - ( {x}^{2}  + 2x + 1)  + 4

simplify parentheses:

y =  -  {x}^{2}  - 2x - 1 + 4

simplify addition:

y =  -  {x}^{2}  - 2x + 3

therefore our answer is D)y=-x²-2x+3

the domain of the function

x\in \mathbb{R}

and the range of the function is

y\leqslant 4

zeroes of the function:

-  {x}^{2}  - 2x + 3 = 0

\sf divide \: both \: sides \: by \:  - 1

{x}^{2}  + 2x - 3 = 0

\implies \:  {x}^{2} +   3x  - x  +  3 = 0

factor out x and -1 respectively:

\sf \implies \: x(x + 3)   - 1(x  + 3 )= 0

group:

\implies \: (x - 1)(x + 3) = 0

therefore

\begin{cases} x_{1} = 1 \\  x_{2}  =  - 3\end{cases}

4 0
3 years ago
Use ΔPQR below to answer the question that follows: Which fact is not used to prove that PQR is similar to STR? (5 points) Segme
MissTica
If these are the missing choices:
A)  Segments ST and PQ are parallel.
B) Angle P is congruent to itself due to the reflexive property.
C) RP is a transversal line passing ST and PQ.
<span>D) Angles RTS and RQP are congruent due to the Corresponding Angles Postulate.

</span>The fact that is not used to prove that PQR is similar to STR is <span>B) Angle P is congruent to itself due to the reflexive property.
</span>
Reflexive property in the given image is on Angle R not angle P.
7 0
3 years ago
Read 2 more answers
A die is rolled. Match the events mentioned in the first column with their corresponding probability.
lakkis [162]

Answer:

Step-by-step explanation:

a number greater than 5 - 1/6

a prime number - 1/2

a number greater than 4 - 1/3

a number less than 6 - 5/6

4 0
3 years ago
8s+4(4s-3)=4(6s+4)-4​
elena55 [62]

Answer:

There is no solution.

5 0
3 years ago
PLEASE HELP ILL GIVE BRAINLIST. In ΔABC shown below, segment DE is parallel to segment AC:
Gnom [1K]

Answer:

a

Step-by-step explanation:

4 0
2 years ago
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