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OLga [1]
3 years ago
5

What is the equation of the line (in point-slope form) that is parallel to y+2=−7(x+3) and passes through the point (1,4)?

Mathematics
1 answer:
bulgar [2K]3 years ago
4 0

Answer:

  y−4=−7(x−1)

Step-by-step explanation:

The point-slope form of the equation for a line with slope m through point (h, k) is ...

  y -k = m(x -h)

Your given line has a slope of -7. The parallel line will have the same slope.

So, you want to fill in the above form with m=-7, (h, k) = (1, 4):

  y -4 = -7(x -1)

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Need help pleaseeeeeeeeee
sukhopar [10]
4log6-log2 =
4log(6/2)=
4log3=
log3⁴=
log81= approximately 1.9085

but I think they want you to stop at log 81
8 0
3 years ago
Does this look correct?
Neko [114]
That is not correct.  I will help you.  Begin by subtracting the 9x from both sides, like this:  9x - 9x + 2y = 6 - 9x.  That simplifies to 2y = -9x + 6.  Now divide both sides by 2 to get y all alone, like this:  \frac{2y}{2}=- \frac{9}{2}x+ \frac{6}{2}.  That reduces down to y=- \frac{9}{2}x+3.  That is slope-intercept form.  y = mx + b.
7 0
2 years ago
Cada uno de los 28 estudiantes en la clase de Romi recaudó al menos $ 25 durante el jump-a-thon. ¿Cuál es la menor cantidad de d
Crank

Answer:

$700.00 porque si cada uno recaudo por lo menos $25.00 entonces multiplicas 28 por los estudiantes y $25.00 por la cantidad menos recaudada equivalente a $700.00

Step-by-step explanation:


7 0
2 years ago
The number of lines that can be drawn perpendicular to a given line at a given point on that line in a plane is
Neko [114]
Only one.
it has a long proof.
3 0
3 years ago
Read 2 more answers
How do I find the inverse function of this equation
trapecia [35]

Answer:

y=ln(x/(1-x))

Step-by-step explanation:

y=e^x/(1+e^x)

Cross multiply

y(1+e^x)=e^x

Distribute

y+ye^x=e^x

Put anything with x on with side and everything without x on opposing side:

y=e^x-ye^x

Factor right hand side

y=(1-y)e^x

Divide both sides by (1-y)

y/(1-y)=e^x

Use natural log.

ln(y/(1-y))=x

The inverse is

y=ln(x/(1-x))

4 0
3 years ago
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