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Firdavs [7]
3 years ago
13

Please solve this if you can

Mathematics
1 answer:
Lunna [17]3 years ago
3 0

Answer:

d = 3

Step-by-step explanation:

(7d+3)/4 = 6

Multiply each side by 4

(7d+3)/4*4 = 6*4

(7d+3) = 24

Subtract 3 from each side

7d+3-3 = 24-3

7d = 21

Divide by 7

7d/7 = 21/7

d = 3

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Two sides of a right triangle are 8’ and 12’ find the area of the triangle if 8 and 12 are a leg hypotenuse
jeka94

so you are tryna find the hypotenuse right?

C = your hypotenuse

C² = A² + B²

C² = 8² + 12²

C² = 64 + 144

C² = 208

C = √208

= 14.42 /14.43

so you can check your answer like, (answer)². hope this helps.

8 0
3 years ago
What is the equation of the line that passes through (0,-3) and (2, 2)?
tigry1 [53]

Answer:

y = \frac{5}{2}x -3

Step-by-step explanation:

Given points (0,-3) (2, 2), we can start by solving for the slope of the line by using the formula:

m = \frac{y2 - y1}{x2 - x1}

Let (x1, y1) = (0,-3)

(x2, y2) = (2, 2)

Plug in these values into the slope formula:

m = \frac{y2 - y1}{x2 - x1} = \frac{2 - (-3)}{2 - 0} = \frac{5}{2}

Therfore, the slope of the line is \frac{5}{2}.

Next, we must determine the y-intercept of the line. By definition, the y-intercept is the y-coordinate of the point where the graph of the linear equation crosses the y-axis. The y-intercept is also the value of y when x = 0.

Using the slope (m) =  \frac{5}{2} and one of the given points, (2, 2), plug in these values into the  slope-intercept form, y = mx + b:

y = mx + b

y = \frac{5}{2}x + b

2 = \frac{5}{2}(2) + b

2 = 5 + b

Subtract 5 on both sides of the equation to solve for b:

2 - 5 = 5 + b - 5

-3 = b

The y-intercept (b) = -3.

Therefore, the equation of the line that passes through (0,-3) and (2, 2) is:

y = \frac{5}{2}x -3.

4 0
3 years ago
Plzzzz help I am stuck on number 4
Nat2105 [25]

Answer:

lol nah <3

Step-by-step explanation:

i would try and help, but not with that trump pfp my dude

8 0
3 years ago
Find the volume of the figure.
-Dominant- [34]
The correct answer would be A. Hope this helps
4 0
3 years ago
Miriam reduced a square photo by cutting 3 inches away from the length and the width so it will fit in her photo album. The area
Rina8888 [55]

Answer:

11 inches by 11 inches

Step-by-step explanation:

The dimensions of the original photo were 11 inches by 11 inches.

We are informed that the area of the reduced photo is 64 square inches and that In the equation (x – 3)^2 = 64, x represents the side measure of the original photo.

In order to solve for x, we shall first take square roots on both sides of the equation;

The square root of (x – 3)^2 is simply (x - 3).

The square root of 64 is ±8 but we ignore -8 since the dimensions of any figure must be positive.

Therefore, we have the following equation;

x - 3 = 8

x = 8 + 3

x = 11

3 0
4 years ago
Read 2 more answers
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