Step-by-step explanation:
The frequency of a radio wave that has a wavelength of 3000m is 100 kHz
(a) Wavelength = 500 m
We know that,
(b) Frequency, f = 800 kHz
Hence, this is the required solution.
Answer:
m(m-3)=108
Step-by-step explanation:
Complete question below:
Two positive integers are 3 units apart on a number line. Their product is 108.
Which equation can be used to solve for m, the greater integer?
m(m – 3) = 108
m(m + 3) = 108
(m + 3)(m – 3) = 108
(m – 12)(m – 9) = 108
Solution
On the number line,
Let
m= larger integer
The integers are 3 numbers apart on the number line, so
m-3=smaller integer
The product (×) of the larger and smaller integers=108
(m)*(m-3)=108
m(m-3)=108
Therefore, the equation that can be used to solve for m, the larger integer is:
m(m – 3) = 108
Answer:
x^9-1,0^3
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