The area as a function of b is given by

You want to find b such that a(b) = 36.
... (2/3)b^3 +6b = 36
... b^3 +9b -54 = 0 . . . . multiply by 3/2 to clear fractions
A graphing calculator shows this equation to have one real solution at b=3.
The value of b is 3.
Answer:
D
Step-by-step explanation:
Given a tangent and a secant from an external point to the circle, then
The product of the external part and the whole secant is equal to the square of the tangent, that is
8(8 - 6 + 2x) = 12²
8(2 + 2x) = 144 ( divide both sides by 8 )
2 + 2x = 18 ( subtract 2 from both sides )
2x = 16 ( divide both sides by 2 )
x = 8
Then
GH = - 6 + 2x = - 6 + 2(8) = - 6 + 16 = 10 → D
Answer:
lol i think its false and ik the pain
Step-by-step explanation:
A² - 225 = (a-15)(a+15)
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Force = mass x acceleration