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Jobisdone [24]
3 years ago
13

Mrs.Rodriguez is going to use 6 1/3 yards of material to make two dresses. The larger dress requires 3 2/3 yards of material. Ho

w much material will Mrs. Rodriguez have left to use on the smaller dress? (NEED ANSWER ASAP!)
Mathematics
2 answers:
Ludmilka [50]3 years ago
8 0
She has 6 1/3. The larger dress need 3 2/3. So 6 1/3 - 3 2/3 = 2 2/3
So Mrs. Rodriguez will need 2 2/3 for the smaller dress
Dima020 [189]3 years ago
3 0

Answer:

Step-by-step explanation:

Given that Mrs.Rodriguez is going to use 6 1/3 yards of material to make two dresses. The larger dress requires 3 2/3 yards of material.

Convert these into improper fractions.

Total material available = \frac{19}{3} yards

Material used for larger dress =\frac{11}{3} yards

Hence material Mrs. Rodriguez have left to use on the smaller dress

= \frac{19}{3}-\frac{11}{3}\\= 2 2/3 yards

answer is 2 2/3 yards

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Answer:

1 1/2 cups of peanut butter

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5 1/2 teaspoon vanilla extract

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Step-by-step explanation:

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3 0
2 years ago
Find the nature of the root
GREYUIT [131]

Answer:

1) Real and same.

2) Real and distinct

3) Real and distinct

4) Real and distinct

5) Real and distinct

6) Real and distinct

7) Real and distinct

8) Real and distinct

Step-by-step explanation:

If a quadratic equation is in the form of ax² + bx + c = 0, then Discriminant of the equation D = b² - 4ac, which governs the nature of roots the equation has.

If D > 0, then there will be two different real roots.

If D = 0, then two same and real roots.

If D < 0, then two distinct but imaginary roots.

Now, 1) x² + 6x + 9 = 0 has D = 6² - 4 × 9 × 1 = 0. So, there will be two same and real roots.

2) 5x² - x = 4x² + 2

⇒ x² - x - 2 = 0

It has D = (-1)² - 4 × 1 × (-2) = 9. Therefore, the roots will be two distinct and real.

3) \frac{2}{x} + \frac{3}{x} = x - 4

⇒ 5 = x² - 4x

⇒ x² - 4x - 5 = 0.

So, D = (-4)² - 4 × (1) × (- 5) = 36. So, the equation has two real and distinct rools.

4) x(x - 5) = 4(5 - x)

⇒ x² - x - 20 = 0

Hence, D = (-1)² - 4 × 1 × (-20) = 81

So, the roots will be real and distinct.

5) x² + 7x + 1 = 0 has D = 7² - 4 × 1 × 1 = 45

So, the roots will be real and distinct.

6) 2x² + 9x + 3 = 0, has D = 9² - 4 × 2 × 3 = 57.

Hence, the roots will be real and distinct.

7) 5x² - 6 = 13x

⇒ 5x² - 13x - 6 = 0

So, D = (-13)² - 4 × 5 × (-6) = 289

So, the roots will be real and distinct.

8) x² - x = 3(x + 7)

⇒ x² - 4x - 21 = 0

It has D = (-4)² - 4 × 1 × (-21) = 100

So, the roots will be real and distinct. (Answer)

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