PLEASE HELP! I JUST NEED SOMEONE TO GRAPH MY ANSWER! I HAVE THE ANSWER, JUST NEED THE GRAPH!
1 answer:
Let
e = Gibson Explorer’s = 20
v = Gibson Flying V’s
So, our problem is
<u>Maximize</u>
Money = 80e + 5v<span>
<u>Subject to</u>
0 </span>≤ <span>e ≤ 20
</span>0 ≤ v ≤ 20
0 ≤ e + v ≤ 30
In order to solve this problem, we look at the graph (attached), and find the value of Money =80e + 5v at corner points to find the maximum value of money.
(e,v)=(0,0) >> Money = 80e+5v = 80*0+5*0 = 0
(e,v)=(0,20) >> Money = 80e+5v = 80*0+5*20 = 100
(e,v)=(20,0) >> Money = 80e+5v = 80*20+5*0 = 1600
(e,v)=(20,10) >> Money = 80e+5v = 80*20+5*10 = 1650 (maximum)
(e,v)=(10,20) >> Money = 80e+5v = 80*10+5*20 = 900
So Bob can make the <u>most money = $1,650</u> when he makes and sell
e = <span>Gibson Explorer’s = 20
</span>v = Gibson Flying V’s = 10
e = Gibson Explorer’s = 20
v = Gibson Flying V’s
So, our problem is
<u>Maximize</u>
Money = 80e + 5v<span>
<u>Subject to</u>
0 </span>≤ <span>e ≤ 20
</span>0 ≤ v ≤ 20
0 ≤ e + v ≤ 30
In order to solve this problem, we look at the graph (attached), and find the value of Money =80e + 5v at corner points to find the maximum value of money.
(e,v)=(0,0) >> Money = 80e+5v = 80*0+5*0 = 0
(e,v)=(0,20) >> Money = 80e+5v = 80*0+5*20 = 100
(e,v)=(20,0) >> Money = 80e+5v = 80*20+5*0 = 1600
(e,v)=(20,10) >> Money = 80e+5v = 80*20+5*10 = 1650 (maximum)
(e,v)=(10,20) >> Money = 80e+5v = 80*10+5*20 = 900
So Bob can make the <u>most money = $1,650</u> when he makes and sell
e = <span>Gibson Explorer’s = 20
</span>v = Gibson Flying V’s = 10
You might be interested in
Answer:
The probability that the mean receipt for dinner is between $24.50 and $25.50 is
P(24.50≤ x ≤ 25.50)= 0.8324
Step-by-step explanation:
<u><em>Step(i)</em></u>:-
Given mean of Population(μ) = $25
Given standard deviation of the Population (σ) = 2.30
Sample size 'n' = 40
Let 'X' be the random variable in normal distribution
Given X₁ = 24.50
Given X₂ = 25.50
<u><em>Step(ii):-</em></u>
The probability that the mean receipt for dinner is between $24.50 and $25.50
P(x₁≤ x ≤ x₂) = P(Z₁≤ z ≤ Z₂) = A(Z₂) + A(z₁)
P(24.50≤ x ≤ 25.50) = P(-1.375≤ z ≤ 1.375) = A(1.375) + A(1.375)
P(24.50≤ x ≤ 25.50)= 2 A( 1.375)
= 2 × 0.4162 ( from normal table)
= 0.8324
<u><em>Final answe</em></u>r:-
The probability that the mean receipt for dinner is between $24.50 and $25.50 is 0.8324
Answer:
A: Function <em>f</em>.
Step-by-step explanation:
Let's find the maximum <em>y-</em>value of each function.
Function <em>f </em>is given by:
Remember that the value of cosine is always between -1 and 1. In other words:
Then assuming the greatest value for cosine, we can substitute it for one:
Function <em>g</em> is given by the graph.
Looking at the graph, we can see that the maximum <em>y-</em>value of <em>g</em> is 3.
Finally, function <em>h</em> is given by the table.
Looking at the table, the maximum <em>y-</em>value of <em>h</em> is -2.
Therefore, function <em>f</em> has the greatest maximum <em>y-</em>value.