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Step2247 [10]
3 years ago
13

I don't understand what I'm supposed to do here. I have a test on this tomorrow so if you explain how to do it that would be gre

at.

Mathematics
1 answer:
VladimirAG [237]3 years ago
7 0
Here is a little tip for this: The unit above cancels the unit below. So in this problem you are asked to convert pounds to ounce. So your equation will look like this. 

ounce = 2.93 pounds ( \frac{16 ounces}{1 pounds} ) = 46.88
Your ratio should involve the conversion factor. So 16 and 1 is involved canceling A and D. Then, Notice that you started with poubls. Then the ratio must have pounds at the bottom to cancel the units leaving ounces. 
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What is the approximate circumference of a circle with a diameter of 14 inches, rounded to the nearest inch? (Use 3.14 as an app
soldi70 [24.7K]

Answer:

44 in.

Step-by-step explanation:

pi = 3.14 (in our case)

circumference = diameter x pi

circ. = 14 x 3.14, which equals to 43.96

round that and you get 44 in.

5 0
2 years ago
If you bought a stock last year for a price $21, and it has risen 11% since then, how much is the stock worth now, to the neares
Lady_Fox [76]

Answer:

$23.31

Step-by-step explanation:

$21 x 1.11 = $23.31

7 0
3 years ago
Does the graph display a function?<br>​
PolarNik [594]
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3 0
3 years ago
Read 2 more answers
Suppose that the length of a phone call in minutes is an exponential random variable with parameter λ = 1/ 8. If someone arrives
Elis [28]

Answer:

a) P=0.535

b) P=0.204

c) P=0.286

Step-by-step explanation:

The exponential distribution is expressed as

F(x>t)=e^{-\lambda t}

In this example, λ=1/8=0.125 min⁻¹.

a) The probability of having to wait more than 5 minutes

F(x>5)=e^{-0.125*5}=e^{-0.625}=0.535

b) The probability of having to wait between 10 and 20 minutes

F(1020)=e^{-0.125*10}-e^{-0.125*20}\\\\F(10

c) The exponential distribution is memory-less, so it is independent of past events.

If you have waited 5 minutes, the probability of waiting more than 15 minutes in total is the same as the probability of waiting 15-5=10 minutes.

F(x>15|t^*=5)=F(x>15)/F(x>5)=\frac{e^{-0.125*15}}{e^{-0.125*5}}=e^{-0.125*(15-5)}\\\\ F(x>15|t^*=5)=e^{-0.125*(10)}=F(x>10)=0.286

5 0
3 years ago
Please please help me I can figure this out :-,(
LenaWriter [7]

It's around 255

I hope this helps

7 0
3 years ago
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