We have that El Paso is 320 miles from Tucson and 720 miles from San Diego.
You're travelling from Tucson to San Diego.
First we have to find the distance from Tucson to San Diego. We can do this by finding the difference between the distance of Tucson from San Diego and El Paso from San Diego.
That is:
720−320
400 miles
You leave by 6:00 am.
You drive for 75 miles per hour in 4 hours for the first part of the journey.
You then drive for 50 miles per hour for the rest of the journey.
The first step is to find the distance that the rest of the journey took. We can do that by first finding the distance covered in the first part of the journey and subtracting that from the total distance (400 miles).
To find the distance for the first part of the journey, we apply the formula for speed (rate of change of distance with time):
s = d/t
⇒d = s⋅t
where d= distance; t = time
Therefore:
d=75⋅4
d=300 miles
The first part of the journey covered 300 miles. This means that the rest of the journey covered:
400 - 300 = 100 miles
Now, to find the time the rest of the journey took, we have to apply the same formula for speed:
s=d/t
t=d/s
Therefore:
t=100/50
t=2 hrs
To find the total time it took to complete the journey, we have to add the times for the first part and the rest of the journey.
That is:
T=4+2
T=6 hours
Since you left home by 6:00 am, the time you will get to San Diego is 6 hours after that, i.e. 12 noon (Tucson time)
That is the answer.
Answer:
k=-7
Step-by-step explanation:
2k-6-7+3k=-48
Combine like terms
5k -13 = -48
Add 13 to each side
5k-13+13 = -48+13
5k = -35
Divide by 5
5k/5 = -35/5
k =-7
I am pretty sure the answer would be (a)
Answer:
x = 24
Step-by-step explanation:
Since this is a right angle, we can use the Pythagorean Theorem to find x. In the formula, a^2 + b^2 = c^2, variables a and b represent the lengths of the legs, and variable c represents the length of the hypotenuse.
a^2 + b^2 = c^2
18^2 + x^2 = 30^2
324 + x^2 = 900
x^2 = 576
x = 24
Answer:
SEE BELOW IN BOLD.
Step-by-step explanation:
a.
h = -16t^2 + 50t
h = 20 t
When the height is the same:
-16t^2 + 50t = 20t
-16t^2 + 30t = 0
t(-16t + 30) = 0
t = 0 or -16t + 30 = 0, so:
t = 0 or -30/-16 = 1.875
So the answer is 1.88 seconds to the nearest hundredth.
b.
For the ball
h = -16t^2 + 50t
Finding the derivative and equating to zero:
dh/dt = -32t + 50 = 0
t = -50/-32 = 1.563
Maximum height after 1.56 seconds to nearest hundredth
c.
When the ball hits the ground h = 0 so
-16t^2 + 50t = 0
-16t(t - 50/16)= 0
T = 3.13 SECONDS TO THE NEAREST HUNDERDTH
