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Musya8 [376]
3 years ago
14

Which function has real zeros at x = -10 and x = -6

Mathematics
1 answer:
kap26 [50]3 years ago
6 0
If it has zeros at x=(-6,-10) the factors of the equation are:

(x+6)(x+10) so the equation is the expansion of what is on the left...

f(x)=x^2+16x+60
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Solve by completing a square r^2-8r+9
Tanzania [10]

Solving  r^2-8r+9 by completing a square gives (r+4)^2-7

Step-by-step explanation:

We need to solve the equation r^2-8r+9 by completing a square

The completing a square method requires: a^2\pm 2ab +b^2=(a\pm b)^2

Solving:

r^2-8r+9\\=(r)^2-2(r)(?)+(?)^2+9

We need to add and subtract (4)^2=16 to make the equation a complete square

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So, Solving  r^2-8r+9 by completing a square gives (r+4)^2-7

Keywords: Solve by completing a square

Learn more about Solve by completing a square at:

  • brainly.com/question/7932185
  • brainly.com/question/1414350
  • brainly.com/question/1464739

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4 years ago
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