I think the. answer is 511.2
Answer:
57.5
Step-by-step explanation:
The expected frequency of West Campus and Failed :
Let :
Failed = F
East Campus = C
West Campus = W
Passed = P
Frequency of FnW :
[(FnE) + (FnW) * (PnW) + (FnW)] / total samples
[(52 + 63) * (63 + 37)] / 200
[(115 * 100)] / 200
11500 / 200
= 57.5
n(Failed n East campus)
I think it might be 1/5 cup maybe
we have

Step 1
Eliminate the parenthesis

Step 2
Group terms that contain the same variable

Step 3
Combine like terms

therefore
the answer is

We have to find the quotient :
( 4 x³ y + 12 x² y³ - 20 x y ) / ( 4 x y ) =
= 4 x y ( x² + 3 x y² - 5 ) / ( 4 x y ) = ( Then 4 x y will be cancelled )
= x² + 3 x y² - 5
Answer:
D ) x² + 3 x y² - 5