The length of bills backyard swimming pool is 60 feet longer than the width of the pool. The surface area of the water is 1600 s
quare feet . What is the width and length of the pool
1 answer:
Answer:
The width is 20 ft and the length is 80 ft
Step-by-step explanation:
Area = l * w
l = w +60
SA = 1600 ft^2 ( which is the regular area) The surface area of the water is just what is on top which is length times width
1600 = l*w
Substitute in l = w+60
1600 = (w+60) *w
Distribute the w
1600 = w^2 +60w
Subtract 1600 from each side
1600-1600 = w^2 + 60w -1600
0 = w^2 + 60w -1600
Factor
0=(w-20) (w+80)
Using the zero product property
w-20=0 w+80 =0
w=20 or w=-80
The width cannot be negative so
w=20
Now we need to find the length
l = w+60
l = 60+20
l =80
You might be interested in
Answer:
Answer is 3bu2(DeEZ)=1
Step-by-step explanation:
Answer:
yes the aswure is no
Step-by-step explanation:
Answer:
The 1,3,and 4.
Step-by-step explanation:
Answer:
x= -1/9
Step-by-step explanation:
6+2x=5-7x
-2x. -2x
6=5-9x
-5. -5
1=-9x/-9
-1/9=x
Answer:
<h2>
67.7</h2><h2 />
Step-by-step explanation:
perimeter = semicircle (x2) + parallelogram side (x2)
= 1/2 π 12 (x2) + 15 (x2)
= 37.7 + 30
= 67.7