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dexar [7]
3 years ago
12

Multiply the following polynomials, then place the answer in the proper location on the grid. Write the answer in descending pow

ers of x.
(8x + 3)(4x + 7)
Mathematics
1 answer:
attashe74 [19]3 years ago
4 0
32x^2+64x+12x+21 => 32x^2+76x+21 you multiply the two equation together and you will get this
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Round 99.59 to the nearest whole number
yarga [219]
The answer would be 100 

8 0
3 years ago
Read 2 more answers
The cost of 1 watermelon and 5 oranges is $11.The cost of 3 watermelons and 5 oranges is $24.50.How much is the cost of 1 waterm
nignag [31]

Answer:

$6.75

Step-by-step explanation:

1: In this explanation, let's let one watermelon be w, and one orange be o.

2: From the passage, 1w + 5o = $11.

3: Also from the passage, 3w + 5o = $24.50

4: We can then use a simultaneous equation to work them out - both equations we have use 5 oranges.

3w + 5o = 24.5 (equation 1)

1w + 5o = 11 (equation 2)

5: We can now take the second equation away from the first :

3w - 1w = 2w, 5o - 5o = 0, 24.5 - 11 = 13.5

Now we know 2w = 13.5

6: If 2w = $13.50, one watermelon will be half of that, so $6.75

Hope this helps, let me know if you have any further questions :)

8 0
2 years ago
Simplify -10x - x plzzzz help
Marta_Voda [28]

hi <3

this is a lot simpler if you just ignore the variable (basically the letter)

now you have -10 - 1

which gives you -11

now just add back on the variable to give you your answer of:

-11x

hope this helps :)

4 0
3 years ago
The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of m
UkoKoshka [18]

Answer:

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

Step-by-step explanation:

Assuming this question: The delivery times for all food orders at a fast-food restaurant during the lunch hour are normally distributed with a mean of 14.7 minutes and a standard deviation of 3.7 minutes. Let R be the mean delivery time for a random sample of 40 orders at this restaurant. Calculate the mean and standard deviation of \bar X Round your answers to two decimal places.

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the delivery times of a population, and for this case we know the distribution for X is given by:

X \sim N(14.7,3.7)  

Where \mu=14.7 and \sigma=3.7

Since the distribution of X is normal then we know that the distribution for the sample mean \bar X is given by:

\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})

And we have;

\mu_{\bar X}= 14.70

\sigma_{\bar X} =\frac{3.7}{\sqrt{40}}= 0.59

4 0
3 years ago
Someone please help me I’ll give out brainliest please dont answer if you don’t know
LiRa [457]

Answer:

turtles are vulnerable. so A is your correct answer

Step-by-step explanation:

6 0
3 years ago
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