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2 years ago

Help me please!!!!!!!!

Mathematics

1 answer:

Over [174]2 years ago

5 0

Step-by-step explanation:

To solve the equation for s we've got to leave s alone

$n = \frac{s + 360}{180} \\ 180n = s + 360 \\ 180n - 360 = s$

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The perimeter of a rectangle is 34 units. Its width is 6.5 point, 5 units.

12345 [234]

<h3><u>Question:</u></h3>

The perimeter of a rectangle is 34 units. Its width W is 6.5 units.

Write an equation to represent the perimeter in terms of the length L, and find the value of L

<h3><u>Answer:</u></h3>

The length of rectangle is 10.5 units

<h3><u>Solution:</u></h3>

Given that,

Perimeter of rectangle = 34 units

Width of rectangle = 6.5 units

Let "L" be the length of rectangle

<em><u>The perimeter of rectangle is given by formula:</u></em>

Perimeter = 2(length + width)

<em><u>Substituting the values we get,</u></em>

$34 = 2(L + 6.5)$

Thus the equation is found

<em><u>Solve for "L"</u></em>

$L + 6.5 = \frac{34}{2}\\\\L + 6.5 = 17\\\\L = 17 - 6.5\\\\L =10.5$

Thus length of rectangle is 10.5 units

6 0

3 years ago

True or false the image of the point (-8,-5) under a reflection across the y-axis is (8,-5)

kakasveta [241]

False. A reflection over the y-axis would result in: (-8,5)

7 0

3 years ago

Pls help! I WILL MARK BRAINLIEST IF YOU ARE CORRECT

Anna11 [10]

The correct answer is C

8 0

2 years ago

3-2/a divided by 5+ 3/a

Svet_ta [14]

For this case we must simplify the following expression:

$\frac {3- \frac {2} {a}} {5+ \frac {3} {a}}$

So, we have:

$\frac {\frac {3a-2} {a}} {\frac {5a + 3} {a}} =$

We apply double C:

$\frac {a (3a-2)} {a (5a + 3)} =$

We simplify:

$\frac {3a-2} {5a + 3}$

Answer:

The simplified expression is:

$\frac {3a-2} {5a + 3}$

6 0

3 years ago

A marble paperweight shaped similar to a cone weighs 0.15 lb. How much does a similarly shaped paperweight weigh if its radius a

solniwko [45]

Answer:

The weight of the enlarged paperweight is $1.2\ lb$

Step-by-step explanation:

we know that

If two figures are similar, then the ratio of its volumes (or its weights) is equal to the scale factor elevated to the cube

Let

z-----> the scale factor

x ----> the enlarged paperweight weight

y ----> the original paperweight weight

$z^{3}=\frac{x}{y}$

we have

$z=2$

$y=0.15\ lb$

substitute and solve for x

$2^{3}=\frac{x}{0.15}$

$x=2^{3}(0.15)=1.2\ lb$

8 0

2 years ago