The fundamental theorem of algebra states that a polynomial with degree n has at most n solutions. The "at most" depends on the fact that the solutions might not all be real number.
In fact, if you use complex number, then a polynomial with degree n has exactly n roots.
So, in particular, a third-degree polynomial can have at most 3 roots.
In fact, in general, if the polynomial 
has solutions 
, then you can factor it as
So, a third-degree polynomial can't have 4 (or more) solutions, because otherwise you could write it as
But this is a fourth-degree polynomial.
Answer:
Step-by-step explanation:
a+√b
a-√b
If lane's are span is 61 inches. his height is 1/4 foot long than his arm span. his height is <span>5 ft 3 inches </span>
Answer:
Step-by-step explanation:
we know that
The <u><em>conjugate root theorem</em></u> states that if the complex number a + bi is a root of a polynomial P(x) in one variable with real coefficients, then the complex conjugate a - bi is also a root of that polynomial
In this problem we have that
The polynomial has roots 1 and (1+i)
so
by the conjugate root theorem
(1-i) is also a root of the polynomial
therefore
The lowest degree of the polynomial is 3
so
Remember that
The leading coefficient is 1
so
a=1
![f(x)=(x-1)(x-(1+i))(x-(1-i))\\\\f(x)=(x-1)[x^{2} -(1-i)x-(1+i)x+(1-i^2)]\\\\f(x)=(x-1)[x^{2} -x+xi-x-xi+2]\\\\f(x)=(x-1)[x^{2} -2x+2]\\\\f(x)=x^{3}-2x^{2} +2x-x^{2} +2x-2\\\\f(x)=x^{3}-3x^{2} +4x-2](https://tex.z-dn.net/?f=f%28x%29%3D%28x-1%29%28x-%281%2Bi%29%29%28x-%281-i%29%29%5C%5C%5C%5Cf%28x%29%3D%28x-1%29%5Bx%5E%7B2%7D%20-%281-i%29x-%281%2Bi%29x%2B%281-i%5E2%29%5D%5C%5C%5C%5Cf%28x%29%3D%28x-1%29%5Bx%5E%7B2%7D%20-x%2Bxi-x-xi%2B2%5D%5C%5C%5C%5Cf%28x%29%3D%28x-1%29%5Bx%5E%7B2%7D%20-2x%2B2%5D%5C%5C%5C%5Cf%28x%29%3Dx%5E%7B3%7D-2x%5E%7B2%7D%20%2B2x-x%5E%7B2%7D%20%2B2x-2%5C%5C%5C%5Cf%28x%29%3Dx%5E%7B3%7D-3x%5E%7B2%7D%20%2B4x-2)
