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Charra [1.4K]
3 years ago
7

James works in a flower shop. he will put 36 tulips in vase for a wedding. he must use the same number of tulips in each vade. t

he number of tulips in each vase must be greater than 1 and less than 10. how many tulips could be in each vase ?
Mathematics
2 answers:
Debora [2.8K]3 years ago
8 0
There is more than one answer. The amount of tulips in each vase if there is more than one and less than 10 with a total of 36 will be of the following:
2 each in 18 vases
3 each in 12 vases
4 each in 9 vases
6 each in 6 vases
9 each in 4 vases
pshichka [43]3 years ago
7 0

Answer:

We have 36 tulips and a undefined number of vases, we want to put the same amount of tulips in each vase and the number of tulips in each vase must be greater than 1 and less than 10. To solve this, we have to find the divisors of 36 (i.e., the list of all integers that divide 36) which are greater than 1 and less than 10; these numbers are: 2, 3, 4, 6 and 9. These are the number of tulips per vase. The number of vases is the quotient between the total amount of tulips and the number of tulips per vase, that is:

tulips per vase    number of vases

2                           36/2 = 18

3                           36/3 = 12

4                           36/4 = 9

6                           36/6 = 6

9                           36/9 = 4

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mixas84 [53]

Answer:

The teacher can purchase 61 pencils with $5

Step-by-step explanation:

This is a simple proportion problem. It can be solved by pure logic reasoning without any formulas

It a dozen pencils cost $0.97, each pencil cost $0.97/12=0.08083

With $5 she will be able to purchase 5/0.08083=61.85 pencils

We must round to the nearest lower integer

The teacher can purchase 61 pencils with $5

6 0
3 years ago
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Answer:

yes the statement is true

Step-by-step explanation:

if you plug in 1^2 you are just multiplying 1 by its self

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3 years ago
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7 0
3 years ago
please help me, Prove a quadrilateral with vertices G(1,-1), H(5,1), I(4,3) and J(0,1) is a rectangle using the parallelogram me
mestny [16]

Answer:

Step-by-step explanation:

We are given the coordinates of a quadrilateral that is G(1,-1), H(5,1), I(4,3) and J(0,1).

Now, before proving that this quadrilateral is a rectangle, we will prove that it is a parallelogram. For this, we will prove that the mid points of the diagonals of the quadrilateral are  equal, thus

Join JH and GI such that they form the diagonals of the quadrilateral.Now,

JH=\sqrt{(5-0)^{2}+(1-1)^{2}}=5 and

GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5

Now, mid point of JH=(\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

=(\frac{5+0}{2},\frac{1+1}{2})=(\frac{5}{2},1)

Mid point of GI=(\frac{5}{2},1)

Since, mid point point of JH and GI are equal, thus GHIJ is a parallelogram.

Now, to prove that it is a rectangle, it is sufficient to prove that it has a right angle by using the Pythagoras theorem.

Thus, From ΔGIJ, we have

(GI)^{2}=(IJ)^{2}+(JG)^{2}                             (1)

Now, JI=\sqrt{(4-0)^{2}+(3-1)^{2}}=\sqrt{20} and GJ=\sqrt{(0-1)^{2}+(1+1)^{2}}=\sqrt{5}

Substituting these values in (1), we get

5^{2}=(\sqrt{20})^{2}+(\sqrt{5})^{2} }

25=20+5

25=25

Thus, GIJ is a right angles triangle.

Hence, GHIJ is a rectangle.

Also, The diagonals GI=\sqrt{(4-1)^{2}+(3+1)^{2}}=5  and HJ=\sqrt{(0-5)^2+(1-1)^2}=5 are equal, thus, GHIJ is a rectangle.

6 0
3 years ago
In the collection of beads, StartFraction 4 Over 20 EndFraction are blue. Which model shows the percent of beads that are blue?
jolli1 [7]

Option B model shows the percent of beads that are blue.

Solution:

Fraction of beads blue = \frac{4}{20}

To convert it into percent multiply the fraction by 100.

$\text {Percent of} \ \frac{4}{20}=\frac{4}{20}\times 100\%

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Cancel the common factors, we get

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This means total number of boxes 100 and shaded in blue color 20.

Therefore option 2 represents \frac{20}{100}.

Hence option B model shows the percent of beads that are blue.

8 0
3 years ago
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