Answer: idk you can figure it out urself
Step-by-step explanation:
Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
z = (x - μ)/σ
Substituting given values, you have
3.6 = (x - 132)/20
(20)(3.6) = x - 132 . . . . multiply by 20
72 + 132 = x . . . . . . . . .add 132
204 = x
The value that has a z-score of 3.6 is 204.
Answer:
Thnx Bro
U to
Step-by-step explanation: