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harina [27]
3 years ago
5

If Jose divides his cards into 8 equal stacks, how many cards will there be in each stack? Will there be any cards left over?

Mathematics
1 answer:
gavmur [86]3 years ago
8 0
Idk how many start cards there are o this problem cant be solved...
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5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim
Ne4ueva [31]

Answer:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

S_p=2.940

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

df=60+72-2=130

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

n_1 =60 represent the sample size for people who used a self service

n_2 =72 represent the sample size for people who used a cashier

\bar X_1 =5.2 represent the sample mean for people who used a self service

\bar X_2 =6.1 represent the sample mean people who used a cashier

s_1=3.1 represent the sample standard deviation for people who used a self service

s_2=2.8 represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that  

\sigma^2_1 =\sigma^2_2 =\sigma^2

The statistic is given by:

t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}

And t follows a t distribution with n_1+n_2 -2 degrees of freedom and the pooled variance S^2_p is given by this formula:

\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}

System of hypothesis

Null hypothesis: \mu_1 \geq \mu_2

Alternative hypothesis: \mu_1 < \mu_2

This system is equivalent to:

Null hypothesis: \mu_1 - \mu_2 \geq 0

Alternative hypothesis: \mu_1 -\mu_2 < 0

We can find the pooled variance:

\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643

And the deviation would be just the square root of the variance:

S_p=2.940

The statistic is given by:

t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751

The degrees of freedom are given by:

df=60+72-2=130

And now we can calculate the p value with:

p_v =P(t_{130}

Assuming a significance level of \alpha=0.05 we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

5 0
3 years ago
What is 9+-234*37^2-38/483
STatiana [176]
37292827 the answer is that
6 0
3 years ago
Read 2 more answers
Find the ratio of x to y if 7/x = 5/y. Help me!!!!
MakcuM [25]
7/x = 5/y
Can be changed to:
5x = 7y
So, x = (7/5)y and
y = (5/7)x

6 0
3 years ago
Inscribed circles on the arc; improvement answer is required in full.
e-lub [12.9K]

Answer:

The measure of an inscribed angle is half the measure of the intercepted arc

∠EFG creates Arc EDG

if ∠EFG is 1/2 arc EDG then 115° x 2 = 230°

A circle is 360°.

The remaining arc EFG is 360° - 230° = 130°

∠EDG is 1/2 of arc EFG so, 130° ÷ 2 = 65°

∠EDG = 65°

8 0
3 years ago
The following graph shows a bus’s record of the number of passengers it picked up over the course of a day. A bar graph titled B
Setler [38]

Answer:

(A)55

Step-by-step explanation:

\left|\begin{array}{c|ccccccccccccccc}x(Time)&7&8&9&10&11&12&1&2&3&4&5&6\\y(Passsengers)&40&62&58&43&36&55&41&28&31&37&75&64\end{array}\right|

From the values on the graph which is presented in the table above, the number of people who rode the bus during the 12.00 hour is 55.

<u>The correct option is A.</u>

7 0
3 years ago
Read 2 more answers
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