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3 years ago

Please help asap!! Thank you

Mathematics

1 answer:

djyliett [7]3 years ago

6 0

Step-by-step explanation:

Hey, there!!

Let's simply work with it,

60° + 2x° + (2x+12)° = 180° { being a linear pair}.

or, 72° + 4x = 180°

4x = 180° - 70°

$x = \frac{108}{4}$

Therefore, the value of x is 27°.

Now,

2x° = (2×27)°= 54°

(2x+12)° = 2×27°+12°= 66°.

(x+2)= 27+ 2= 29°

Now, The left angle is 27°.

Therefore, The answer is option A.

Hope it helps...

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What does a path become a circuit and a cycle

Afina-wow [57]

Answer:

We do not travel to the same vertex twice (or more). A cycle is a closed path. ... Different books have different terminology in some books a simple path means in which none of the edges are repeated and a circuit is a path which begins and ends at same vertex,and circuit and cycle are same thing in these books.

Step-by-step explanation:

7 0

3 years ago

PLEASE HELP!! Algebra 2

lawyer [7]

Answer:

Edit:

Yes, based on original equation. (Credit to greenpumpkin for correction)

Step-by-step explanation:

For this problem, we simply need to find the values of x that can make the equation true. So, let's begin by isolating the "x" variable.

sqrt(2x + 13) = x + 5

[sqrt(2x + 13)]^2 = (x + 5)^2

2x + 13 = x^2 + 10x + 25

0 = x^2 + 8x + 12

Note, we can remove the sqrt method by squaring both sides of the equation. Doing this, we see we have a quadratic equation meaning we can apply the quadratic formula to find solutions for x.

[-b +/- sqrt( b^2 - 4(a)(c) ) ] / 2a

Let a = 1, b = 8, and c = 12

[-8 +/- sqrt( (8)^2 - 4(1)(12) ) ] / 2(1)

= [-8 +/- sqrt( 64 - 48 ) ] / 2

= [-8 +/- sqrt(16) ] / 2

= [ -8 +/- 4 ] / 2

So, x = [ -8 + 4 ] / 2 and x = [-8 - 4 ] / 2

x = [-4] / 2 = -2 and x = [-12] / 2 = -6

Hence, the two values of x that can solve this quadratic equation are x = -2 and x = -6.

Therefore, we know that x = -6 is not extraneous, meaning it is a solution to our equation.

Cheers.

----------------------------------------------------

Edit:

Plugging the value of -6 back into the original equation, we get the following:

sqrt(2x + 13) = x + 5

sqrt(2(-6) + 13) = (-6) + 5

sqrt (1) = -1

1 != -1

Given that 1 cannot equal negative 1, we can say that x = -6 is an extraneous solution. (Credit to greenpumpkin for correction)

8 0

2 years ago

Hello there ^ _ ^ Can you help me please ? Please explain how you find the answer. Thanks!

ziro4ka [17]

It's C because for the perpendicular line, you need to construct cross points to draw it through.

- you start by drawing a random circle with F as the center, just as long as it intersects line DE
- Then you use the intersections of that circle to draw new circles starting at F.
- These new circles intersect at F and another point below DE.
- You draw the perpendicular line through F and the other point.

8 0

3 years ago

The cubic polynomial below has a double root at r4 and one root at x = 6 and passes Through the point (2, 36) as shown. Algebrai

qaws [65]

The graph in the question is missing.

Answer:

y = $\frac{-1}{4}( x^3 + 2x^2 - 32x -96)$

Step-by-step explanation:

The function is cubic

It has roots as -4, -4 , 6

this means the value of x = -4, -4 , 6 which makes the entire equation zero

so we have solutions as

x+4 = 0

x- 6 = 0

on forming a cubic equation using these

(x+4)(x+4)(x-6)

the equation passes through (2,36)

put x = 2

(2+4)(2+4)(2-6) = (6)*(6)*(-4)

which exceeds 36 so we product the equation with -1/4 to get 36

Final equation

y = $\frac{-1}{4} (x+4)(x+4)(x-6)$

y = $\frac{-1}{4}( x^3 + 2x^2 - 32x -96)$

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Lelu [443]

You would be facing southwest

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3 years ago

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