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marysya [2.9K]
3 years ago
7

Find the area of a right triangle with a base of 14 m and a height of 4 m.

Mathematics
2 answers:
olga nikolaevna [1]3 years ago
7 0

Answer:

28

Step-by-step explanation:

1/2 bh

1/2 x 14 x 4

7 x4

=28m

Veseljchak [2.6K]3 years ago
5 0

Answer:

area of a right triangle = ab / 2

                     base     = 14 m

                  height     = 4 m

area = 14 * 4 / 2 = 56/2 = 28

∴ area = 28 m^{2}

hope this answer helps you.....

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A=4

The work behind it

-11a+33= -11
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-44/-11=a
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Six less than seven times a number is equal to-12
Vanyuwa [196]
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PLEASEE HELP!!
Alex777 [14]

Answer:

<h2>A)t=6.7</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
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<h3>given:</h3>

h(t) = -4t² + 12t + 100

<h3>to solve:</h3>

t

<h3>tips and formulas:</h3>
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<h3>let's solve: </h3>

step - 1 :  \: define

- 4 {t}^{2}  + 12t + 100 = 0

step - 2 :  \\ divide \: both \: sides \: by \:  - 4

{t}^{2}  - 3t - 25 = 0

step - 3 :  \\ solve \: the \: quadratic

formula :  \\ x =  \frac{ - b± \sqrt{ {b}^{2} - 4ac }  }{2a}

define \: a ,b \: and \: c \\ which \: are \: 1, - 3 \: and \:  - 25 \: respectively

t =  \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4.1. - 25 }  }{2.1}

t =  \frac{  3± \sqrt{ 9    + 100}  }{2}

t = \frac{3 +  \sqrt{ 109 } }{2}

t =  \frac{3  -  \sqrt{ 109 } }{2}

t = 6.7 \\ t =  - 3.7

as \: we \: know \: time \: cannot \: be \: negative

\huge \therefore \: t = 6.7

5 0
3 years ago
X^2-18x+67=0 Solve the quadratic equation by completing the square.
Assoli18 [71]

Answer:

x = 9 ± √14

Step-by-step explanation:

x² − 18x + 67 = 0

Move the constant to the other side:

x² − 18x = -67

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x² − 18x + 81 = -67 + 81

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Solve for x:

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zimovet [89]

Answer:

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Step-by-step explanation:

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Thus, the simplest form is \frac{4}{5}

7 0
2 years ago
Read 2 more answers
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