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Fiesta28 [93]
4 years ago
15

For a service call a plumber chargers a 95$ initial fee plus 45$ for each hour he works.write a equation to represent the total

cost,C dollors for T hours or work.
Mathematics
2 answers:
leonid [27]4 years ago
8 0
The equation would be 95+45T=C
ratelena [41]4 years ago
7 0
The answer is 95C+45T
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To download 5 albums it would be $60.
Explanation: $36 divided by 3 is $12.
5 x $12= $60.
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3 years ago
Read 2 more answers
1.
RUDIKE [14]

Answer:

Answer:

For converging lens

object distance u = - 2.0cm

Focal length f = 5.0cm

From lens formula

m=

m=

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Size of image = size of object x Magnification

= 2 x .10 = 2.0cm

For diverging lens

object distance u = 140 - 120 = 20 cm

focal length f = -30 cm

frac{1}{v}+\frac{1}{20}=-\frac{1}{30}

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Which graph represents an exponential function<br><br> graphs in comments
Sladkaya [172]
I don’t know can’t see it
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3 years ago
In the diagram, A||B and B||C. Find the values of X.
Airida [17]

Answer:

31

Step-by-step explanation:

3x + 12 and 105 are alternate exterior angles because A || B and B || C.

If the two or more lines are parallel, then the alternate exterior angles are equal.

3x + 12 = 105

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3x = 105 - 12

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Divide 3 on both sides,

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7 0
3 years ago
Suppose you have a box with 3 blue marbles, 2 red marbles, and 4 yellow marbles. You are going to pull out one marble, record it
prohojiy [21]

The probability of randomly getting first a red marble and then a blue marble is:

P = 0.083

<h3>How to find the probability?</h3>

There are:

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For a total of 9 marbles.

The probability of getting a red marble is equal to the quotient between the number of red marbles and the total, so:

P(red) = 2/9

Then the probability of getting a blue marble is equal to the quotient between the number of blue marbles and the total, but because we already took one marble, now the total is 8.

P(blue) = 3/8

The joint probability is given by the product:

P = (2/9)*(3/8) = 0.083

If you want to learn more about probability:

brainly.com/question/25870256

#SPJ1

7 0
2 years ago
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