Answer:
Hey there!
We don't have enough information. 7(n+5) can be written as either the 7 times the sum of n+5, or 7 multiplied by n+5.
Let me know if this helps :)
Answer:
(-1, 4)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
10x + 6y = 14
-x - 6y = -23
<u>Step 2: Solve for </u><em><u>x</u></em>
<em>Elimination</em>
- Add 2 equations together: 9x = -9
- Divide 9 on both sides: x = -1
<u>Step 3: Solve for </u><em><u>y</u></em>
- Define original equation: -x - 6y = -23
- Substitute in <em>x</em>: -(-1) - 6y = -23
- Multiply: 1 - 6y = -23
- Subtract 1 on both sides: -6y = -24
- Divide -6 on both sides: y = 4
The answer is it should be behind the 7 because you only moved one time in 1.7
Answer:
Answer:
3x + 3y = 0
7x - y = 8
Step-by-step explanation:
Answer:
46
Step-by-step explanation:
