If the discriminant of a quadratic equation, given by B^2-4AC is positive, it has 2 real solutions. If 0, it has 1 real solution and if negative it has 0 real solutions.
We are given the following equation and want to find the possible values of x
Subtract both sides by 3x
Now, we have this weird equation. Since -15 is NOT equal 15 and there is no other way we could have solved for x, there is no real solution to the given equation.
In other words, there is no value of x that makes the equation true.
Let me know if you need any clarifications, thanks!
~ Padoru
Answer:
1x+6x=35 7x=35 x=35 divided by 7 x=5 first game 5x6=30 second
Step-by-step explanation:
You take the first equation and make a value for y. So 6x + y =7 change it to :
y = -6x + 7
Now in the second equation replace the “y” with -6x +7 this is what it means to use substitution method . Your combined equation will now be :
8x + 9(-6x + 7) =17
Now do distributive property and you get :
8x + -54x +63 =17
Now combine like terms ;
-46x +63 =17
-46x =-46
x = 1
Now replace 1 for X value and we can get the value of Y .
Y=1
X=1
Answer:
how much time did it take him???????
Step-by-step explanation:
