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Lelechka [254]
3 years ago
8

Find the value of the variable for which the value of the expression –3(2x+1) is 20 greater than the value of the expression 8x+

5
Mathematics
1 answer:
Charra [1.4K]3 years ago
6 0
<h3>Answer:</h3>

-2

<h3>Step-by-step explanation:</h3>

20 greater than 8x +5 is ...

... 8x +5 +20 = 8x +25

We want this value to be -3(2x +1), so we want to solve the equation ...

... 8x +25 = -3(2x +1)

... 8x +25 = -6x -3 . . . . . . eliminate parentheses

... 14x = -28 . . . . . . . . . . . add 6x-25

... x = -2 . . . . . . . . . . . . . . divide by the coefficient of x

The desired value of the variable is -2.

_____

<u>Check</u>

-3(2x+1) = -3(2(-2)+1) = -3(-3) = 9

8x+5 = 8(-2) +5 = -11

9 is 20 greater than -11, so the answer checks OK.

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Answer:

The absolute maximum and minimum is 20\; \text{and} -20.

Step-by-step explanation:

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Along boundary  y=16-x^2

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\begin{array}{}(4,0)=-16\\(-4,0)=16\\(0,16)=0\\(2,14)=20\\(-2,14)=-20\end{array}

Therefore, the absolute maximum and minimum is 20\; \text{and} -20.

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