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3 years ago

The graph shows two lines, K and J.

Mathematics

2 answers:

swat323 years ago

4 0

(1,1) is the solution to both lines which is the correct answer

topjm [15]3 years ago

4 0

Answer:

The correct option is 1.

Step-by-step explanation:

If a system of equations have two equation of lines. Then the intersection point of both lines is the solution of given system of equations.

The given graph contains two lines. All the points lie on the line are the solution of that line.

From the given graph it is clear that both the line intersect each other at point (1,1). It means both lines passes through the point (1,1). So, (1,1) is the solution of system of equations.

Since (1, 1) is the solution to both lines K and J. Therefore the correct option is 1.

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3 years ago

The perimeters of square region S and rectangular region R are equal. If the sides of R are in the ratio 2 : 3, what is the rati

Ksivusya [100]

<h2>Answer:</h2>

The ratio of the area of region R to the area of region S is:

$\dfrac{24}{25}$

<h2>Step-by-step explanation:</h2>

The sides of R are in the ratio : 2:3

Let the length of R be: 2x

and the width of R be: 3x

i.e. The perimeter of R is given by:

$Perimeter\ of\ R=2(2x+3x)$

( Since, the perimeter of a rectangle with length L and breadth or width B is given by:

$Perimeter=2(L+B)$ )

Hence, we get:

$Perimeter\ of\ R=2(5x)$

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$Perimeter\ of\ R=10x$

Also, let " s " denote the side of the square region.

We know that the perimeter of a square with side " s " is given by:

$\text{Perimeter\ of\ square}=4s$

Now, it is given that:

The perimeters of square region S and rectangular region R are equal.

i.e.

$4s=10x\\\\i.e.\\\\s=\dfrac{10x}{4}\\\\s=\dfrac{5x}{2}$

Now, we know that the area of a square is given by:

$\text{Area\ of\ square}=s^2$

and

$\text{Area\ of\ Rectangle}=L\times B$

Hence, we get:

$\text{Area\ of\ square}=(\dfrac{5x}{2})^2=\dfrac{25x^2}{4}$

and

$\text{Area\ of\ Rectangle}=2x\times 3x$

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$\text{Area\ of\ Rectangle}=6x^2$

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3 years ago

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Step-by-step explanation:

Hey there!

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Hope it helps..

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3 years ago