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elena55 [62]
4 years ago
13

Is it true that ƒ −(g − h) = (ƒ − g) − h? Explain why you believe the equation is true or provide a counterexample to show that

it is not.
Mathematics
1 answer:
miss Akunina [59]4 years ago
5 0

Answer:

The expression is false

Step-by-step explanation:

Given

f - (g - h) = (f - g) - h

Required

True or False

To determine if the expression is true or false, we need to simplify both sides of the equation

f - (g - h) = (f - g) - h

<em></em>

<em>Start by opening the bracket on the right hand side</em>

<em></em>f - (g - h) = f - g - h<em></em>

<em></em>

<em>Then open the bracket on the left</em>

<em></em>f - g + h = f - g - h<em></em>

<em></em>

<em>Subtract f - g from both sides</em>

<em></em>f - g - (f - g) + h = f - g - (f - g) + h<em></em>

<em></em>f - g - f + g + h = f - g - f + g - h<em></em>

<em></em>f - f - g + g + h = f - f - g + g - h<em></em>

<em></em>h \neq -h<em></em>

<em></em>

<em>Hence;</em>

<em>The statement is false</em>

<em></em>

<em>To further check;</em>

<em>Assume f = 5; g = 4 and h = 3</em>

f - (g - h) = (f - g) - h becomes

5 - (4 - 3) = (5 - 4) - 3

5 - 4 + 3 = 5 - 4 - 3

2 \neq -2

<em></em>

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si la suma de dos veces el primer numero entero y tres veces el segundo entero es 48, cuales son los enteros?
Vlad1618 [11]

Hello from MrBillDoesMath!

Answer:

The integers cannot be uniquely determined


Discussion:

Let the first integer be "f" and the second integer "s".

From the Question

2f + 3s = 48


The values f and s can NOT be uniquely determined.

For example, f = 24, s = 0 is one solution.

f = 0, s = 16 is another....

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See the problem?  The Question needs to be clarified



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Step-by-step explanation:

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nadya68 [22]
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</span>
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Volume:
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AURORKA [14]
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