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3 years ago

What is the equation for the line that has a slope of 0 and passes through the point (3, 7)?

Mathematics

1 answer:

Harrizon [31]3 years ago

6 0

Answer:

Step-by-step explanation:

PART 1

y=mx+b

m is slope and slope is 0 sooo

y=0x+b

it passes through (3,7)

7=0(3)+b

7=0+b

b=7

y=0x+7

so just y=7

PART 2

y=mx+b

y=1/5x+b

1/2=1/5(-2/3)+b

1/2=-2/15+b

1/2+2/15=b

15/30+4/30=b

19/30=b

y=1/5x+19/30

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Answer:

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Step-by-step explanation:

8(6-4)=12

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Read 2 more answers

PLEASE HELP ASAP <br>are f(x)=4/x-2-1 and g(x)=3/x+2-2 inverses of each other?

GREYUIT [131]

Answer:

To find the inverse of:

$f (x)=\dfrac{4}{x-2}-1$

Set the function to y:

$\implies y=\dfrac{4}{x-2}-1$

Rearrange to make x the subject:

$\implies y+1=\dfrac{4}{x-2}$

$\implies (y+1)(x-2)=4$

$\implies xy-2y+x-2=4$

$\implies xy+x=2y+6$

$\implies x(y+1)=2y+6$

$\implies x=\dfrac{2y+6}{y+1}$

Swap x and y:

$\implies y=\dfrac{2x+6}{x+1}$

Change y to the inverse of the function sign:

$\implies f$ $\:^{-1}(x)=\dfrac{2x+6}{x+1}$

Rewrite g(x) as a fraction:

$g(x)=\dfrac{3}{x+2}-2$

$\implies g(x)=\dfrac{3}{x+2}-\dfrac{2(x+2)}{x+2}$

$\implies g(x)=\dfrac{3-2(x+2)}{x+2}$

$\implies g(x)=\dfrac{3-2x-4}{x+2}$

$\implies g(x)=-\dfrac{2x+1}{x+2}$

Therefore, as the inverse of f(x) ≠ g(x), the functions are NOT inverses of each other

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1 year ago

Please help 3(2x+1)+2(x+4)

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Step-by-step explanation:

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3 years ago