15 inches
i found it on https://answers.yahoo.com/question/index?qid=20160331230251AA3MILQ
At a track meet, Jacob and Daniel compete in 220 m hurdles.
Daniels finishes in of the a min.
Jacob finishes with of a min remaining.
Question:
Who ran the race in faster time?
The Process:
Let us see the denominators. The least common multiple (LCM) of 4 and 12 is 12.
Let us draw the diagram that represents a minute.
12 units represent in one minute.
Daniels finishes in of the a min.
or 9 of 12 units.
Jacob finishes with of a min remaining, or 5 of 12 units. This means Jacob finishes in or 7 of 12 units, that is
And now we conclude who ran the race in a faster time.
Daniels:
Jacobs:
Because Jacob took the race in a shorter time, he was who ran the race in a faster time.
- - - - - - - - - -
Quick Steps
Daniels: in of the a min.
Jacob: in of the a min.
Jacob's time is shorter, so he's the fastest.
- - - - - - - - - -
Calculate the speed
Recall
Daniels:
Jacob:
Thus, Jacob's speed proved greater than Daniels's speed.
Answer:
-2 -4
Step-by-step explanation:
saying to use 20 letters lol hope that helps
The distance between city C and city D is 450 miles.
<u>Solution:</u>
Given, The distance between City A and City B is 250 miles.
A length of 2.3 feet represents this distance on a certain wall map.
City C and City D are 4.14 feet apart on this map.
We have to find what is the actual distance between City C and City D?
Now, distance between a and b is 250 miles ⇒ 2.3 feet on map
Then, distance between c and d be n miles ⇒ 4.14 feet on map.
Now, by chris cross method.
250 x 4.14 = 2.3 x n miles.
2.3n = 1035
n = 450
Hence, the distance between city C and city D is 450 miles.
Answer: 0.3679
Step-by-step explanation:
The cumulative distribution function for exponential distribution is :-
, where
is the mean of the distribution.
Given : A mean length of waiting time equal
minutes
i.e. Mean number of calls answered in a minute ![\lambda=\dfrac{1}{2.8}](https://tex.z-dn.net/?f=%5Clambda%3D%5Cdfrac%7B1%7D%7B2.8%7D)
Now, the proportion of callers is put on hold longer than 2.8 minutes is given by :_
![P(x>2.8)=1-P(x](https://tex.z-dn.net/?f=P%28x%3E2.8%29%3D1-P%28x%3C2.8%29%5C%5C%5C%5C%3D1-%281-e%5E%7B-%5Cfrac%7B1%7D%7B2.8%7D%5Ctimes2.8%7D%29%5C%5C%5C%5C%3D1-1%2Be%5E%7B-1%7D%5C%5C%5C%5C%3De%5E%7B-1%7D%5C%5C%5C%5C%3D0.367879441171%5Capprox0.3679)
Hence, the proportion of callers is put on hold longer than 2.8 minutes = 0.3679