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4 years ago

What is 363 rounded to the nearest ten and hundred

Mathematics

2 answers:

slega [8]4 years ago

7 0

363 rounded to tenth is going to be 360

and rounded to hundredth is going to be 400

hope it helps :)

anyanavicka [17]4 years ago

4 0

3 is less than 5, so rounded to the nearest ten is 360.

6 is greater than 5, so rounded to the nearest hundred, our answer is 400.

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Y= -0.25x + 4.7<br> Y=4.9x - 1.64

Andreas93 [3]

Answer:

The answer would be (1.23, 4.39)

Step-by-step explanation:

Because they are both equal to y, we can set the equations equal to each other and then solve.

4.9x - 1.64 = -0.25x + 4.7

5.15x - 1.64 = 4.7

5.15x = 6.34

x = 1.23

Now that we have the value for x, we can plug into either equation and find y.

y = -0.25x + 4.7

y = -0.25(1.23) + 4.7

y = -.31 + 4.7

y = 4.39

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3 years ago

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What is the measure of an angle whose sine is√3/2 ? 60 45 30

dem82 [27]

ANSWER

The required angle is
$60 \degree$

EXPLANATION

Let the angle whose sine is
$\frac{ \sqrt{3} }{2}$
be
$x \degree$

Then

$\sin(x \degree) = \frac{ \sqrt{3} }{2}$

We take the inverse sign of both sides to obtain,

$x = \sin ^{ - 1} ( \frac{ \sqrt{3} }{2} )$

We use our scientific calculator to evaluate and obtain,

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3 years ago

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Evaluate the expression <br>18C14

Anton [14]

Answer:

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Step-by-step explanation:

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3 years ago

Select True or False from each pull-down menu, depending on whether the corresponding statement is true or false.

Schach [20]

Answer:

1) FALSE

2) FALSE

3) TRUE

4) TRUE

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Part 1

The mean and standard deviation of a normally distributed random variable which has been standardized are one and zero, respectively.

The mean and the deviation for the normal standard distribution are:

$\mu=0, \sigma =1$

So then that's FALSE.

Part 2

Using the standard normal curve, the z−score representing the 10th percentile is 1.28.

We are looking for a value a, that satisfy this:

$P(X>a)=0.90$ (a)

$P(X$ (b)

We can find a z value that satisfy the condition with 0.10 of the area on the left and 0.90 of the area on the right it's z=-1.28. On this case P(Z<-1.28)=0.10 and P(Z>-1.28)=0.90

So that's FALSE.

Part 3

Let z1 be a z−score that is unknown but identifiable by position and area. If the symmetrical area between −z1 and +z1 is 0.9544, the value of z1 is 2.0

If we find this probability:

$P(-2.0< Z$

So on this case we can approximate to 0.9544. And that's TRUE.

Part 4

Using the standard normal curve, the z−score representing the 75th percentile is 0.67.

We are looking for a value a, that satisfy this:

$P(X>a)=0.25$ (a)

$P(X$ (b)

We can find a z value that satisfy the condition with 0.75 of the area on the left and 0.25 of the area on the right it's z=0.67. On this case P(Z<0.67)=0.75 and P(Z>0.67)=0.25

So that's TRUE.

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