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likoan [24]
9 months ago
6

a small batch of Trail Mix contains 2 cups of raisins, two cups of peanuts, one cup of sunflower seeds, and one cup of chocolate

coated candies. A large batch has the same ratio of ingredients as a small batch. If the large batch has 8 cups of peanuts, how many cups of sunflower seeds are in a large batch?
Mathematics
1 answer:
Nana76 [90]9 months ago
8 0

4 cups of sunflower seeds in a large batch

Explanation:

Small batch:

cups of raisins = 2

cups of peanuts = 2

cup of sunflower seeds = 1

cup of chocolate coated candies = 1

The ratio: 2:2:1:1

Large batch:

cups of peanuts = 8

cups of sunflower seeds are in a large batch = ?

From the small batch, we know for every 1 cup of sunflower seeds, we would have 2 cups of peanuts.

let the number of cup of sunflower seeds used in large batch = y

1 cup of sunflower seeds = 2 cups of peanuts

y = 8 cups of peanuts

cross multiply:

1(8) = 2(y)

8 = 2y

Divide both sides by 2:

8/2 = 2y/2

4 = y

Hence, the number of cups of sunflower seeds in a large batch is 4

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As x decreases y also decreased
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2 years ago
The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacemen
mamaluj [8]
<h2>Answer:</h2>

(a)

The probability is :  1/2

(b)

The probability is :  1/2

<h2>Step-by-step explanation:</h2>

The numbers​ 1, 2,​ 3, 4, and 5 are written on slips of​ paper, and 2 slips are drawn at random one at a time without replacement.

The total combinations that are possible are:

(1,2)   (1,3)    (1,4)    (1,5)

(2,1)   (2,3)   (2,4)   (2,5)

(3,1)   (3,2)   (3,4)   (3,5)

(4,1)   (4,2)   (4,3)   (4,5)

(5,1)   (5,2)   (5,3)   (5,4)

i.e. the total outcomes are : 20

(a)

Let A denote the event that the first number is 4.

and B denote the event that the sum is: 9.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

We know that it could be calculated by using the formula:

P(A|B)=\dfrac{P(A\bigcap B)}{P(B)}

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( Since, out of a total of 20 outcomes there is just one outcome which comes in A∩B and it is:  (4,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 9

(4,5) and (5,4) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

(b)

Let A denote the event that the first number is 3.

and B denote the event that the sum is: 8.

Let P denote the probability of an event.

We are asked to find:

               P(A|B)

Hence, based on the data we have:

P(A\bigcap B)=\dfrac{1}{20}

( since, the only outcome out of 20 outcomes is:  (3,5) )

and

P(B)=\dfrac{2}{20}

( since, there are just two outcomes such that the sum is: 8

(3,5) and (5,3) )

Hence, we have:

P(A|B)=\dfrac{\dfrac{1}{20}}{\dfrac{2}{20}}\\\\i.e.\\\\P(A|B)=\dfrac{1}{2}

7 0
3 years ago
Adrian's CD player can hold six disks at a time and shuffles all of the albums and their songs. If he has thirteen CD's, how man
Crank
Adrian can put a total of 1716 combinations in the player. 

The formula to be used is as follows:

total combinations = n!/[r! *(n-r)!]
n = number of disks available  = 13
r = number of disks that be held = 6

= 13! = (13• 12•11•10•9•8•7•6•5•4•3•2•1)/(6! <span>• 7!)
</span>=1716

Thank you for posting your question. Feel free to ask me more.



6 0
3 years ago
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Answer:

Please Attach The Pic so someone can answer.....

Step-by-step explanation:

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Answer:

The $1 belongs to the cash box

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine if the $1 belongs to the cash box or not

Represent singles with s and couples with c.

From the attachment, we have:

s + c = 47 --- total attendance

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Solve for s and c.

Make s the subject in (1)

s = 47-c

Substitute 47 - c for s in (2)

5(47 - c) + 4c = 200

Open bracket

235 - 5c + 4c = 200

235 - c = 200

c = 235 - 200

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<em>So, we can conclude that the $1 belongs to the cash box</em>

4 0
2 years ago
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