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aivan3 [116]
3 years ago
12

590 divided by 50779

Mathematics
1 answer:
Strike441 [17]3 years ago
8 0
590/50779= 0.1161898 or 0.116
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Find the point-slope form of the equation of the line that passes through (4, -2) With a slope of 1/4
Anuta_ua [19.1K]
(y+2)=1/4(x-4) is the answer because you use the formula (y-y1)=slope(x-x1)
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Andrew can paint the​ neighbor's house 6 times as fast as The year and worked​ together, it took them 5 days. How long would it
Rina8888 [55]

Answer: \dfrac{35}{6}\ \text{days},\ 35\ \text{days}

Step-by-step explanation:

Given

Andrew can paint  times faster than the other

Suppose the other person take 6x days

So, andrew takes only x days to paint alone

When they work together, it took them 5 days i.e.

\Rightarrow \dfrac{1}{x}+\dfrac{1}{6x}=\dfrac{1}{5}\\\\\Rightarrow \dfrac{6+1}{6x}=\dfrac{1}{5}\\\\\Rightarrow x=\dfrac{35}{6}\ \text{days}

So, time taken by the to finish individually is given by

\Rightarrow \text{Andrew= }\dfrac{35}{6}\ \text{days}\\\\\Rightarrow \text{Other Person}=6\times \dfrac{35}{6}\\\\\Rightarrow \text{Other Person}=35\ \text{days}

5 0
3 years ago
Segment BD is an altitude of triangle ABC. Find the area of the triangle.
Sever21 [200]

Answer: The correct option is A, i.e., 7.5.

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It is given that ABC is a triangle and BD is an altitude.

Since BD is an altitude, therefore the height of the triangle is BD and the base of the triangle is AC.

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D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

First, we find BD, where B(-1,4) and D(2,4).

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So, the height of the triangle is 3.

Now, we find the value of AC, where A(2,1) and C(2,6).

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So, the base of the triangle is 5.

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A=\frac{1}{2}\times {\text{base}}\times {\text{height}}

A=\frac{1}{2}\times 5\times 3=\frac{15}{2}=7.5

Therefore, the area of the triangle is 7.5 unit square and the correct option is A.

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3 years ago
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Find the slope of the line on the graph.
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Answer:

3

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By going up 3 and right 1 you get 3/1, aka 3

The line of the equation is y=3x+2

7 0
3 years ago
How to solve this question
VMariaS [17]
<span>The variance method is as follows.

-Sum the squares of the values in data set, and then divide by the number of values in data set
- From that, subtract the square of the mean (add all values and divide by number of values in the data set)

Our variance is

<span>\displaystyle\sigma^2 = \frac{2^2 + 5^2 + m^2}{3} - \left(\frac{2 + 5 + m}{3}\right)^2

Since variance has to be 14, we set \sigma^2  = 14 and solve for m

14= \frac{4 + 25 + m^2}{3} - \left(\frac{7 + m}{3}\right)^2\ \Rightarrow \\ \\&#10;14 = \frac{29}{3} + \frac{1}{3}m^2 - \frac{1}{9}(7+m)^2 \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{1}{9}(49 + 14m + m^2) \\ \\&#10;14 = \frac{29}{3}+ \frac{1}{3}m^2 - \frac{49}{9}- \frac{14}{9}m- \frac{1}{9}m^2 \\ \\&#10;0 = \frac{-88}{9}  -\frac{14}{9}m + \frac{2}{9}m^2&#10;

quadratic formula


m = \displaystyle\frac{-b \pm \sqrt{b^2 -4ac}}{2a} \\&#10;m = \frac{-(-\frac{14}{9}) \pm \sqrt{\left(-\frac{14}{9}\right)^2 - 4(2/9)(-88/9)} }{2(2/9)} \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{196}{81} + \frac{704}{81} } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{900}{81}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \sqrt{ \frac{100}{9}  } }{\frac{4}{9} } \\&#10;m = \frac{\frac{14}{9} \pm \frac{10}{3}  }{\frac{4}{9} } \\&#10;m = 11, -4

-4 doesnt' work as it is not a positive integer

m = 11


</span></span>
5 0
3 years ago
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