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enot [183]
3 years ago
10

Please answer the everything thank you ! i'll mark the brainlest!!!!! :)

Mathematics
1 answer:
kari74 [83]3 years ago
4 0

Answer:

1. a. 2 KM ; b. 9000 m

2. a. 9 L ; b. 3000 g

3. a.   6000 ml  ; b. 9

4. a. 60 mm ; b. 4000 m

5. a. 1 km     ; b. 2 kg

6. a. 5      ;    b. 4 m

7. a. 4000 ml  ; b. 3000

8. a. 10 kg ; b. 20 mm

9. a. 10 km ; b. 9kg

10. a. 4 kg ; 8 l

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25 POINTS!!!!!!
8_murik_8 [283]
Your anwer is C)<span>f(x) = 467(5 to the one fourth power)4x</span>
7 0
2 years ago
Read 2 more answers
What is the solution set of the equation?<br> <img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%7D%20-18%2B9x%3Dx" id="TexFormula1"
bagirrra123 [75]

9514 1404 393

Answer:

  x ∈ {2.07014981016}

Step-by-step explanation:

The equation can be rewritten as ...

  √x = 18-8x

  x = 324 -288x +64x²

  64x² -289x +324 = 0

  x = (289 ±√577)/128 ≈ {2.07015, 2.44548}

Since √x must be positive, we know that ...

  18 -8x ≥ 0

  x ≤ 18/8 = 2.25

The larger of the above solutions is extraneous, so the solution set is ...

  x ∈ {(289 -√577)/128} ≈ {2.07015}

8 0
2 years ago
A sample of blood pressure measurements is taken for a group of​ adults, and those values​ (mm Hg) are listed below. The values
Slav-nsk [51]

Answer:

Systolic on right

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

Step-by-step explanation:

Assuming the following data:

Systolic (#'s on right) Diastolic (#'s on left)

117; 80

126; 77

158; 76

96; 51

157; 90

122; 89

116; 60

134; 64

127; 72

122; 83

The coefficient of variation is defined as " a statistical measure of the dispersion of data points in a data series around the mean" and is defined as:

CV= \frac{\sigma}{\mu}

And the best estimator is \hat {CV} =\frac{s}{\bar x}

Systolic on right

We can calculate the mean and deviation with the following formulas:

[te]\bar x = \frac{\sum_{i=1}^n X_i}{n}[/tex]

s= \frac{\sum_{i=1}^n (x_i -\bar X)^2}{n-1}

For this case we have the following values:

\bar x = 127.5, s= 18.68

So then the coeffcient of variation is given by:

\hat{CV} =\frac{18.68}{127.5}=0.147

Systolic on left

For this case we have the following values:

\bar x = 74.2 s= 12.65

So then the coeffcient of variation is given by:

\hat{CV} =\frac{12.65}{74.2}=0.170

So for this case we have more variation for the data of systolic on left compared to the data systolic on right but the difference is not big since 0.170-0.147 = 0.023.

4 0
2 years ago
What is 2+2
ad-work [718]

Answer:

4

Step-by-step explanation:

2+2 is 4

5 0
3 years ago
What is 500 divided by 6.7
pishuonlain [190]
\boxed{ \frac{500}{6.7} = 74.627\ Answer}
7 0
3 years ago
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