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KIM [24]
3 years ago
9

I am bad at math plz help

Mathematics
1 answer:
Kay [80]3 years ago
8 0
\sqrt{ \frac{64}{144} }=б  \frac{ \sqrt{64} }{ \sqrt{144} }=   б  \frac{ \sqrt{8^2} }{ \sqrt{12^2} }=б  \frac{8 }{12}

The answer is C. -8/12 and 8/12
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Alex787 [66]

Answer:

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Step-by-step explanation:

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3 years ago
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Amiraneli [1.4K]

Answer:

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Step-by-step explanation:

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3 years ago
At a local acoustic guitar shop, the lute maker sets the strings of the guitars to a height of between 2/32 and 4/32 inches abov
Korolek [52]

Answer:

A: 3/32+1/32 inch

Step-by-step explanation:

So we have the measurements 2/32 and 4/32. We are told the heights range between these two measurements.

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Since the problem says "between", that must mean 2/32 and 4/32 are the limits of the height.

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4 0
3 years ago
Louise calculated the height of a cylinder that has a volume of 486 pi cubic centimeters and a radius of 9 centimeters. Her work
Bumek [7]

Step-by-step explanation:

Louise calculated the height of a cylinder that has a volume of 486 pi cubic centimetres and a radius of 9 centimetres.

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i.e.

V=\pi r^2 h

Substituting given values,

486\pi =\pi (9)^2 \times h

\pi will cancel out from both sides.

486= (9)^2 \times h\\\\h=\dfrac{486}{81}\\\\h=6\ cm

She forgets to cancel down \pi from both sides. So, she get height as 6\pi\ cm. So, in the \pi should have canceled, making the correct answer 6 cm.

3 0
4 years ago
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