Answer:
Step-by-step explanation:
Claim: if the mean amount of garbage per bin is different from 50.
Null hypothesis: u=50
Alternative hypothesis : u =/ 50
Using the z score formular for a one sample z test - z = (x - u ) / (sd/√n)
Where x = 48.99, u = 50 sd =3.7 and n = 36
z = 48.99 - 50 / (3.7/√36)
z = -1.01 / (3.7/6)
z = -1.01/0.6167
z = -1.6377
To find the p value at a 0.01 level of significant from the -1.6377 z score for a two tailed test the p value using the p value calculator is 0.1016. The result is not significant at 0.01 level of significant thus we will fail to reject the null and conclude that the mean amount of garbage per bin is 50.
Answer: 30%
Step-by-step explanation:
Given: Cupcakes have sprinkles = 15
Cupcakes didn't have sprinkles = 35
Total cupcakes = 15+35 = 50
The percentage of the cupcakes had sprinkles =
Hence, the percentage of the cupcakes had sprinkles = 30%
The equation was just flipped around, it will equal the same no matter what.
I hope this helps!! :)
An exponential model can be described by the function
where: a is the initial population or the starting number, b is the base and x is the number of periods elapsed.
When the base of an exponential model is greater than 1 it is called a growth factor, but when it is less than 1 it is called a decay factor.
Given the exponential model
n is the final output of the exponential model, 20.5 is the starting number, 0.6394 is the base and t is the number of periods/time elapsed.
Here, the base is 0.6394 which is less than 1, hence a decay factor.
Therefore, <span>the
base, b, of the exponential model is 0.6394; It is a
decay factor.</span>