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Sati [7]
4 years ago
5

Find the GCF of 189 and 200 using prime factorization

Mathematics
1 answer:
Ronch [10]4 years ago
8 0
The Greatest Common Factor (GCF) of 189 and 200 is 1.
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Will mark Brainly!!! 20 points!!!!
Mumz [18]

Answer:

= 4

Step-by-step explanation:

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to approximate to the nearest whole number (integer), you take the first decimal number which is 8, since 8 is greater than 5, you will add one(1) to the whole number which is 3 to make it 4.

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3 years ago
What is the value in meters per second squared of the acceleration of gravity?
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In real-life physics, acceleration due to gravity will change respect to altitude. Check out the attached image (source: Wikipedia).

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3 years ago
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Eduardwww [97]

Answer:

The 2nd y is 12, the 3rd y is 24 and the last x is 3

Step-by-step explanation:

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3 years ago
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What is the surface area of the right prism given below?
posledela

Answer: Option D.

Step-by-step explanation:

You can calculate the surface area of this right prism by adding the area of its faces.

You can observe that the faces of the right prism are:  Three different rectangles and two equal triangles.

The formula for calculate the  area of a rectangle is:

A=lw

 Where "l" is the lenght and "w" is the width.

The formula for calculate the  area of a triangle is:

A=\frac{bh}{2}

Where "b" is the base and "h" is the height.

You can observe that the hypotenuse of the each triangle is the width of one of the larger rectangle, then , you can find its value with the Pythagorean Theorem:

a=\sqrt{b^2+c^2}

Where "a" is the hypotenuse and "b" and "c" are the legs of the triangle.

Then, this is:

a=\sqrt{(8units)^2+(15units)^2}=17units

Therefore, you can add the areas of the faces to find the surface area of the right prism (Since the triangles are equal, you can multiply the area of one of them by 2). This is:

SA=(10units)(8units)+(15units)(10units)+(17units)(10units)+2(\frac{(15units)(8units)}{2})\\\\SA=520units^2

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3 years ago
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Put 0.875 in a fraction form
KATRIN_1 [288]
I think the answer is 7/8
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3 years ago
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