the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
Step-by-step explanation:
-2 (4a + 4b) + 5a > -35
-8a -8b + 5a > -35
-3a -8b > -35
for a
-3a > -35 + 8b
a < -35 + 8b ÷ -3
a < 35 - 8b ÷ 3
for b
-3a - 8b > -35
-8b > -35 + 3a
b < -35 + 3a ÷ -8
b < 35 - 3a ÷ 8
2(20+60+48)=2(128)= 256 square inches
Hope it helps
Answer: 4
step by step explanation: 3+1=4
