Answer:The answer is 130
Step-by-step explanation:
AC = 9 m; BC = 16.16 m; BD = 28.27 m; CD = 12.12 m
<em>Find AC
</em>
AC = AB = 9 m
<em>Find BC</em>
∠BAC = 2π – 10π/7 = (14π – 10π)/7 = 4π/7
BC = <em>θr</em> = 4π/7 × 9 m = 16.16 m
<em>Find BD
</em>
∠BAD = π
BD = <em>θr</em> = π × 9 m = 28.27 m
<em>Find CD</em>
<em>C</em> = 2π<em>r
</em>
CD = <em>C</em> – BC – BD = 2π<em>r</em> – 4π<em>r</em>/7 – π<em>r</em> = (14π<em>r</em> – 4π<em>r</em> – 7π<em>r</em>)/7 = (3π/7)<em>r</em>
= (3π/7) ×9 m = 12.12 m
5y+30+2y<4y+8
5y+2y-4y<8-30
3y<-22
y<-22/3
Given :
Two vertical buildings 57 meters apart are 158 meters and 237 meters high.
To Find :
The angle of elevation from the top of the shorter building to the top of the taller building.
Solution :
Distance between height of building, h = 237 - 158 = 79 m.
Distance between these building , d = 57 m.
Now,
Therefore, the angle of elevation from the top of the shorter building to the top of the taller building is 54.19°.
Hence, this is the required solution.
The slope of the red line would be the inverse of the green line. so the red line's slope is 1.
Green line: -1/1
Red line:1/1