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For altitudes up to 36,000 feet, the relationship between ground temperature and atmospheric

Verizon [17]

Answer:

The equation for a is $a=-\frac{2000}{7}*(t-g)$

The altitute is 101,428.57 feet

Step-by-step explanation:

You know that the relationship between ground temperature and atmospheric temperature can be described by the formula

t = -0.0035a +g

where:

t is the atmospheric temperature in degrees Fahrenheit
a is the altitude, in feet, at which the atmospheric temperature is measured
g is the ground temperature in degrees Fahrenheit.

Solving the equation for a:

-0.0035a +g=t

-0.0035a= t - g

$a=\frac{t-g}{-0.0035}$

$a=-\frac{2000}{7}*(t-g)$

The equation for a is $a=-\frac{2000}{7}*(t-g)$

If the atmospheric temperature is -305 °F and the ground temperature is 50 °F, then t= -305 °F and g= 50 °F

Replacing in the equation for a you get:

$a=-\frac{2000}{7}*(-305-50)$

$a=-\frac{2000}{7}*(-355)$

a= 101,428.57

The altitute is 101,428.57 feet

4 0

3 years ago

Solve for x. <img src="https://tex.z-dn.net/?f=x%20%2B%206%20-%202x%20%3D%20x%20-%2024" id="TexFormula1" title="x + 6 - 2

zhenek [66]

Greetings from Brasil...

First degree equation. The variables are in the 1st member and the numbers in the 2nd member.

X + 6 - 2X = X - 24

X - 2X - X = - 24 - 6

- 2X = - 30

7 0

3 years ago

Boris drove 240 miles using 9 gallons of gas. At this rate, how many gallons of gas would he need to drive 216 miles?

satela [25.4K]

Use proportion to solve this.
240 miles needs 9 gallons
216 miles needs (9÷240) × 216 = 8.1 gallons

Hope it helped!

6 0

3 years ago

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One card is drawn at random from a deck of 52 cards. The first card is not replaced, and a second card is drawn. (Enter your pro

andriy [413]

Answer:

We have a 52 card deck:

a. Find the probability that both cards are clubs.

The probability of drawing a club will be equal to the quotient between the number of clubs in the deck divided by the total number of cards in the deck.

We initially have 13 clubs and 52 cards, then the probability of drawing a club in the first draw is:

p1 = 13/52.

Now the probability of drawing a club in the second draw will be:

p2 = 12/51

Where each number is decreased by one because we already drew a card, and that card was a club.

Then the probability of both events happening will be equal to the product of the individual probabilities:

P = p1*p2 = (13/52)*( 12/51) = 0.059

b. Find the probability that the first card is a spade and the second is a club.

Same as before, the probability of first drawing a spade is:

p1 = 13/52

And the probability of drawing a club in the second draw will be:

p2 = 13/51

This case differs from the prior one because for the second draw we have 13 clubs in the deck, and as we already drew one card (that was not a club) the total number of cards in the deck is 51.

Now the joint probability will be:

P = p1*p2 = (13/52)*(13/51) = 0.064

3 0

3 years ago

Which statement about perpendicular lines is false?

Alex_Xolod [135]

The statement that is false about perpendicular lines is that the never intersect, making the answer equal to C.

7 0

4 years ago

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