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Airida [17]
4 years ago
10

Graph each system of constraints. Name all vertices. Then find the values of x and y that either maximizes or minimizes the obje

ctive function.
Mathematics
1 answer:
stealth61 [152]4 years ago
5 0

i mean its pretty simple it is math cmon now.


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In the given diagram, if AP = 15 cm, AQ = 24 cm and PB + QC = 26 cm, find QC – PB, given PQ || BC.
Anna35 [415]

Answer:

QC - PB = 6

Step-by-step explanation:

Given PQ is parallel to BC then it divides the sides proportionally, that is

\frac{AP}{AQ} = \frac{PB}{QC} = \frac{15}{24} = \frac{5}{8} , then

\frac{PB}{QC} = \frac{5}{8} ( cross- multiply )

8PB = 5QC → *

Given PB + QC = 26 , then

PB = 26 - QC

Substitute into *

8(26 - QC) = 5QC ← distribute left side

208 - 8QC = 5QC ( subtract 5QC from both sides )

208 - 13QC = 0 ( subtract 208 from both sides )

- 13QC = - 208 ( divide both sides by - 13 )

QC = 16

Thus PB = 26 - QC = 26 - 16 = 10

QC - PB = 16 - 10 = 6

8 0
3 years ago
A store offers a 30% discount on a coat that originally sold for $120. The coat still does not sell, so the store offers another
stiks02 [169]

Answer:

kjjjiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

Step-by-step explanation:

4 0
3 years ago
Question 4
sleet_krkn [62]

Answer:

\displaystyle about\:8\:units

Step-by-step explanation:

Use the Distance Formula:

\displaystyle \sqrt{[-x_1 + x_2]^2 + [-y_1 + y_2]^2} = D \\ \\ \sqrt{[6 - 1]^2 + [-7 + 1]^2} = \sqrt{5^2 + [-6]^2} = \sqrt{25 + 36} = \sqrt{61} ≈ 7,810249676 ≈ 8

Since we are talking about distance, we ONLY want the NON-NEGATIVE root.

I am joyous to assist you anytime.

3 0
3 years ago
Which statement best describes why there is no real solution to the quadratic equation y = x2 - 6x + 13?
Ahat [919]
This is the quadratic equation
x = -b +/- (sq root)(b^2 - 4(a)(c) all over 2a
If inside the square root the value is <0. You can't get an answer.
Now figure the rest out
6 0
3 years ago
If I needed to write in this format (A U B) how would i write it
MAXImum [283]

Answer:

n(AUB)=n(A)+n(B)–n(AnB)

n(AUB)=n⁰(A)+n⁰(B)+n(AnB)

Step-by-step explanation:

This is the formula i have learned. Hope this will help u. U can use them according the question type.

7 0
3 years ago
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