How many subsets of the set of divisors of 72 contain only composite numbers? For example, {8,9} and {4,8,12}$ are two such sets

Question

4 years ago

6

. Include the empty set in your count.

1 answer:

kykrilka [37] · Answer 1 · 2022-02-12T20:06:44+03:00

Answer:

257

Step-by-step explanation:

The divisors of 72 which are composite number are

4,6,8,9,12,18,36,72 (composite numbers are those numbers which are formed by the multiplication of two whole numbers}

So the total number of divisors which are composite are = 8

So total number of subset $=2^n=2^8=256$

In question it is said that also include empty set in count

So total number of subset =256+1=257