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Liono4ka [1.6K]
3 years ago
7

Systems of equations by substitution

Mathematics
1 answer:
Korolek [52]3 years ago
6 0
Could you please clarify the question please by putting a question to be solved? Or are you asking for the definition?
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Find the median for the scores 91, 69, 71, 82, 71, 95, 87, 74, 71, 89, 89, 95, 72, 75
AnnyKZ [126]

\huge\text{Hey there!}

\huge\textbf{What does \boxed{median} mean in math?}}

\boxed{\text{Median}}\rightarrow\textsf{ is the number in the middle.}

\huge\textbf{How do you find the \boxed{median}?}

\text{You can found it by putting the numbers from \bf least to greatest.}

\huge\textbf{Question reads....}

\text{Find the median for the scores 91, 69, 71, 82, 71, 95, 87, 74, 71, 89, 89, 95,}\\\text{72, 75}

\huge\textbf{Equation:}

\text{91, 69, 71, 82, 71, 95, 87, 74, 71, 89, 89, 95, 72, 75}

\huge\textbf{Rearrange the problems to:}

\text{69,71,71,71,72,74,75,82,87, 89,89,91,95,95}

\huge\textbf{The expression:}

\mathsf{\dfrac{75 + 82}{2} = median}

\huge\textbf{Simplify it:}

\mathsf{\dfrac{75 + 82}{2} = median}

\mathsf{\dfrac{157}{2} = median}

\mathsf{257\div2 = median}

\mathsf{78.5 = median}

\huge\textbf{Therefore, your answer should be:}

\huge\boxed{\mathsf{78.5}}\huge\checkmark

\huge\text{Good luck on your assignment \& enjoy your day!}

<h3>~\frak{Amphitrite1040:)}</h3>
8 0
1 year ago
The first number is 14 less than the second number. When she adds them, she gets 40.
Alenkinab [10]

Answer:

second number is 17, first number is 3

Step-by-step explanation:

5 0
3 years ago
I can’t do this rn does someone know what to do??
uranmaximum [27]

Answer:

see image

Step-by-step explanation:

See image. It all on the paper in the picture. Hope this helps! Please mark Brainliest if possible! tysm!

4 0
1 year ago
The temperature was 2.5°C below zero. After 4 hours, the temperature was now 5.6°C
ELEN [110]

Answer:

3.1 degrees celcius

Step-by-step explanation:

5.6C-2.5C=3.1C

5 0
2 years ago
If rx – st = r, which expression represents r.
statuscvo [17]

Answer:

{ \tt{rx - st = r}}

» Collect like terms, r terms on the left hand side by subtracting r from both sides and adding st to both sides

{ \tt{(rx - st) { \green{ - r + st }} = r{ \green{ - r + st}}}} \\ { \tt{rx - r = st}}

» On the left hand side, factorise out r

{ \tt{ \green{r(x - 1)} = st}} \\  \\ { \boxed{ \tt{ \blue{ \: r =  \frac{st}{x - 1} }}}}

5 0
2 years ago
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